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Nonlinear equations

Step by Step Solution

Step  1  :

Equation at the end of step  1  :

  (((0 -  (x4)) +  7x2) -  x) -  17  = 0 

Step  2  :

Step  3  :

Pulling out like terms :

 3.1     Pull out like factors :

   -x4 + 7x2 - x - 17  = 

  -1 • (x4 - 7x2 + x + 17) 

Checking for a perfect cube :

 3.2    x4 - 7x2 + x + 17  is not a perfect cube

Trying to factor by pulling out :

 3.3      Factoring:  x4 - 7x2 + x + 17 

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1:  x + 17 
Group 2:  x4 - 7x2 

Pull out from each group separately :

Group 1:   (x + 17) • (1)
Group 2:   (x2 - 7) • (x2)

Bad news !! Factoring by pulling out fails :

The groups have no common factor and can not be added up to form a multiplication.

Polynomial Roots Calculator :

 3.4    Find roots (zeroes) of :       F(x) = x4 - 7x2 + x + 17
Polynomial Roots Calculator is a set of methods aimed at finding values of  x  for which   F(x)=0  

Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers  x  which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number  P/Q   then  P  is a factor of the Trailing Constant and  Q  is a factor of the Leading Coefficient

In this case, the Leading Coefficient is  1  and the Trailing Constant is  17.

 
The factor(s) are:

of the Leading Coefficient :  1
 
of the Trailing Constant :  1 ,17

 
Let us test ....

  P  Q  P/Q  F(P/Q)   Divisor
     -1     1      -1.00      10.00   
     -17     1     -17.00     81498.00   
     1     1      1.00      12.00   
     17     1      17.00     81532.00   


Polynomial Roots Calculator found no rational roots

Equation at the end of step  3  :

  -x4 + 7x2 - x - 17  = 0 

Step  4  :

Quartic Equations :

 4.1     Solve   -x4+7x2-x-17 = 0

In search of an interavl at which the above polynomial changes sign, from negative to positive or the other wayaround.

Method of search: Calculate polynomial values for all integer points between x=-20 and x=+20

No interval at which a change of sign occures has been found. Consequently, Bisection Approximation can not be used. As this is a polynomial of an even degree it may not even have any real (as opposed to imaginary) roots

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