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Solution - Factoring multivariable polynomials

5(a6p)(a2+6ap+36p2)
5*(a-6p)*(a^2+6ap+36p^2)

Step by Step Solution

Step  1  :

Equation at the end of step  1  :

  (5 • (a3)) -  (23•33•5p3)

Step  2  :

Equation at the end of step  2  :

  5a3 -  (23•33•5p3)

Step  3  :

Step  4  :

Pulling out like terms :

 4.1     Pull out like factors :

   5a3 - 1080p3  =   5 • (a3 - 216p3) 

Trying to factor as a Difference of Cubes:

 4.2      Factoring:  a3 - 216p3 

Theory : A difference of two perfect cubes,  a3 - b3 can be factored into
              (a-b) • (a2 +ab +b2)

Proof :  (a-b)•(a2+ab+b2) =
            a3+a2b+ab2-ba2-b2a-b3 =
            a3+(a2b-ba2)+(ab2-b2a)-b3 =
            a3+0+0-b3 =
            a3-b3


Check :  216  is the cube of   6 
Check :  a3 is the cube of   a1

Check :  p3 is the cube of   p1

Factorization is :
             (a - 6p)  •  (a2 + 6ap + 36p2) 

Trying to factor a multi variable polynomial :

 4.3    Factoring    a2 + 6ap + 36p2 

Try to factor this multi-variable trinomial using trial and error 

 
Factorization fails

Final result :

  5 • (a - 6p) • (a2 + 6ap + 36p2)

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