সমাধান - জ্যামিতিক ধারা

সিরিজের সাধারণ রূপ খুঁজে পেতে, প্রথম পদ: $$a=109$$ এবং সাধারণ অনুপাত: $$r=0.07339449541284404$$ জ্যামিতিক সিরিজের সূত্রে প্লাগ করুন:

$$a_1=109$$

$$a_2=a_1·r^{n-1}=109\cdot {0.07339449541284404}^{2-1}=109\cdot {0.07339449541284404}^1=109\cdot 0.07339449541284404=8$$

$$a_3=a_1·r^{n-1}=109\cdot {0.07339449541284404}^{3-1}=109\cdot {0.07339449541284404}^2=109\cdot 0.0053867519569059845=0.5871559633027523$$

$$a_4=a_1·r^{n-1}=109\cdot {0.07339449541284404}^{4-1}=109\cdot {0.07339449541284404}^3=109\cdot 0.00039535794179126497=0.04309401565524788$$

$$a_5=a_1·r^{n-1}=109\cdot {0.07339449541284404}^{5-1}=109\cdot {0.07339449541284404}^4=109\cdot 2.9017096645230457E-05=0.0031628635343301198$$

$$a_6=a_1·r^{n-1}=109\cdot {0.07339449541284404}^{6-1}=109\cdot {0.07339449541284404}^5=109\cdot 2.129695166622419E-06=0.00023213677316184369$$

$$a_7=a_1·r^{n-1}=109\cdot {0.07339449541284404}^{7-1}=109\cdot {0.07339449541284404}^6=109\cdot 1.5630790213742526E-07=1.7037561332979352E-05$$

$$a_8=a_1·r^{n-1}=109\cdot {0.07339449541284404}^{8-1}=109\cdot {0.07339449541284404}^7=109\cdot 1.1472139606416534E-08=1.2504632170994023E-06$$

$$a_9=a_1·r^{n-1}=109\cdot {0.07339449541284404}^{9-1}=109\cdot {0.07339449541284404}^8=109\cdot 8.419918977186448E-10=9.177711685133227E-08$$

$$a_{10}=a_1·r^{n-1}=109\cdot {0.07339449541284404}^{10-1}=109\cdot {0.07339449541284404}^9=109\cdot 6.179757047476291E-11=6.735935181749157E-09$$