সমাধান - জ্যামিতিক ধারা

সিরিজের সাধারণ রূপ খুঁজে পেতে, প্রথম পদ: $$a=1,221$$ এবং সাধারণ অনুপাত: $$r=1.651105651105651$$ জ্যামিতিক সিরিজের সূত্রে প্লাগ করুন:

$$a_1=1221$$

$$a_2=a_1·r^{n-1}=1221\cdot {1.651105651105651}^{2-1}=1221\cdot {1.651105651105651}^1=1221\cdot 1.651105651105651=2015.9999999999998$$

$$a_3=a_1·r^{n-1}=1221\cdot {1.651105651105651}^{3-1}=1221\cdot {1.651105651105651}^2=1221\cdot 2.726149871113016=3328.6289926289924$$

$$a_4=a_1·r^{n-1}=1221\cdot {1.651105651105651}^{4-1}=1221\cdot {1.651105651105651}^3=1221\cdot 4.501161457955642=5495.918140163839$$

$$a_5=a_1·r^{n-1}=1221\cdot {1.651105651105651}^{5-1}=1221\cdot {1.651105651105651}^4=1221\cdot 7.431893119769512=9074.341499238575$$

$$a_6=a_1·r^{n-1}=1221\cdot {1.651105651105651}^{6-1}=1221\cdot {1.651105651105651}^5=1221\cdot 12.270840728464648=14982.696529455336$$

$$a_7=a_1·r^{n-1}=1221\cdot {1.651105651105651}^{7-1}=1221\cdot {1.651105651105651}^6=1221\cdot 20.260454470585366=24738.01490858473$$

$$a_8=a_1·r^{n-1}=1221\cdot {1.651105651105651}^{8-1}=1221\cdot {1.651105651105651}^7=1221\cdot 33.45215087035224=40845.076212700085$$

$$a_9=a_1·r^{n-1}=1221\cdot {1.651105651105651}^{9-1}=1221\cdot {1.651105651105651}^8=1221\cdot 55.233035343677415=67439.53615463013$$

$$a_{10}=a_1·r^{n-1}=1221\cdot {1.651105651105651}^{10-1}=1221\cdot {1.651105651105651}^9=1221\cdot 91.19557678366392=111349.79925285366$$