সমাধান - জ্যামিতিক ধারা

সিরিজের সাধারণ রূপ খুঁজে পেতে, প্রথম পদ: $$a=99$$ এবং সাধারণ অনুপাত: $$r=0.050505050505050504$$ জ্যামিতিক সিরিজের সূত্রে প্লাগ করুন:

$$a_1=99$$

$$a_2=a_1·r^{n-1}=99\cdot {0.050505050505050504}^{2-1}=99\cdot {0.050505050505050504}^1=99\cdot 0.050505050505050504=5$$

$$a_3=a_1·r^{n-1}=99\cdot {0.050505050505050504}^{3-1}=99\cdot {0.050505050505050504}^2=99\cdot 0.002550760126517702=0.2525252525252525$$

$$a_4=a_1·r^{n-1}=99\cdot {0.050505050505050504}^{4-1}=99\cdot {0.050505050505050504}^3=99\cdot 0.00012882626901604557=0.012753800632588512$$

$$a_5=a_1·r^{n-1}=99\cdot {0.050505050505050504}^{5-1}=99\cdot {0.050505050505050504}^4=99\cdot 6.506377223032604E-06=0.0006441313450802278$$

$$a_6=a_1·r^{n-1}=99\cdot {0.050505050505050504}^{6-1}=99\cdot {0.050505050505050504}^5=99\cdot 3.286049102541719E-07=3.253188611516302E-05$$

$$a_7=a_1·r^{n-1}=99\cdot {0.050505050505050504}^{7-1}=99\cdot {0.050505050505050504}^6=99\cdot 1.659620758859454E-08=1.6430245512708595E-06$$

$$a_8=a_1·r^{n-1}=99\cdot {0.050505050505050504}^{8-1}=99\cdot {0.050505050505050504}^7=99\cdot 8.381923024542697E-10=8.29810379429727E-08$$

$$a_9=a_1·r^{n-1}=99\cdot {0.050505050505050504}^{9-1}=99\cdot {0.050505050505050504}^8=99\cdot 4.233294456839746E-11=4.190961512271349E-09$$

$$a_{10}=a_1·r^{n-1}=99\cdot {0.050505050505050504}^{10-1}=99\cdot {0.050505050505050504}^9=99\cdot 2.138027503454417E-12=2.116647228419873E-10$$