Solution - Finding the roots of polynomials
Other Ways to Solve
Finding the roots of polynomialsStep by Step Solution
Step 1 :
Equation at the end of step 1 :
Step 2 :
14x3 + x2 - 30x + 13
Simplify ————————————————————
7x - 10
Checking for a perfect cube :
2.1 14x3 + x2 - 30x + 13 is not a perfect cube
Trying to factor by pulling out :
2.2 Factoring: 14x3 + x2 - 30x + 13
Thoughtfully split the expression at hand into groups, each group having two terms :
Group 1: -30x + 13
Group 2: 14x3 + x2
Pull out from each group separately :
Group 1: (-30x + 13) • (1) = (30x - 13) • (-1)
Group 2: (14x + 1) • (x2)
Bad news !! Factoring by pulling out fails :
The groups have no common factor and can not be added up to form a multiplication.
Polynomial Roots Calculator :
2.3 Find roots (zeroes) of : F(x) = 14x3 + x2 - 30x + 13
Polynomial Roots Calculator is a set of methods aimed at finding values of x for which F(x)=0
Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers x which can be expressed as the quotient of two integers
The Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading Coefficient
In this case, the Leading Coefficient is 14 and the Trailing Constant is 13.
The factor(s) are:
of the Leading Coefficient : 1,2 ,7 ,14
of the Trailing Constant : 1 ,13
Let us test ....
| P | Q | P/Q | F(P/Q) | Divisor | |||||
|---|---|---|---|---|---|---|---|---|---|
| -1 | 1 | -1.00 | 30.00 | ||||||
| -1 | 2 | -0.50 | 26.50 | ||||||
| -1 | 7 | -0.14 | 17.27 | ||||||
| -1 | 14 | -0.07 | 15.14 | ||||||
| -13 | 1 | -13.00 | -30186.00 | ||||||
| -13 | 2 | -6.50 | -3594.50 | ||||||
| -13 | 7 | -1.86 | -17.51 | ||||||
| -13 | 14 | -0.93 | 30.51 | ||||||
| 1 | 1 | 1.00 | -2.00 | ||||||
| 1 | 2 | 0.50 | 0.00 | 2x - 1 | |||||
| 1 | 7 | 0.14 | 8.78 | ||||||
| 1 | 14 | 0.07 | 10.87 | ||||||
| 13 | 1 | 13.00 | 30550.00 | ||||||
| 13 | 2 | 6.50 | 3705.00 | ||||||
| 13 | 7 | 1.86 | 50.41 | ||||||
| 13 | 14 | 0.93 | -2.79 |
The Factor Theorem states that if P/Q is root of a polynomial then this polynomial can be divided by q*x-p Note that q and p originate from P/Q reduced to its lowest terms
In our case this means that
14x3 + x2 - 30x + 13
can be divided with 2x - 1
Polynomial Long Division :
2.4 Polynomial Long Division
Dividing : 14x3 + x2 - 30x + 13
("Dividend")
By : 2x - 1 ("Divisor")
| dividend | 14x3 | + | x2 | - | 30x | + | 13 | ||
| - divisor | * 7x2 | 14x3 | - | 7x2 | |||||
| remainder | 8x2 | - | 30x | + | 13 | ||||
| - divisor | * 4x1 | 8x2 | - | 4x | |||||
| remainder | - | 26x | + | 13 | |||||
| - divisor | * -13x0 | - | 26x | + | 13 | ||||
| remainder | 0 |
Quotient : 7x2+4x-13 Remainder: 0
Trying to factor by splitting the middle term
2.5 Factoring 7x2+4x-13
The first term is, 7x2 its coefficient is 7 .
The middle term is, +4x its coefficient is 4 .
The last term, "the constant", is -13
Step-1 : Multiply the coefficient of the first term by the constant 7 • -13 = -91
Step-2 : Find two factors of -91 whose sum equals the coefficient of the middle term, which is 4 .
| -91 | + | 1 | = | -90 | ||
| -13 | + | 7 | = | -6 | ||
| -7 | + | 13 | = | 6 | ||
| -1 | + | 91 | = | 90 |
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Final result :
(7x2 + 4x - 13) • (2x - 1)
——————————————————————————
7x - 10
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