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Adding, subtracting and finding the least common multiple

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(26)/(b+5)=1+((3)/b-2)

This solution deals with adding, subtracting and finding the least common multiple.

Solution found

b=(-28-sqrt(844))/2=-14-sqrt(211)=-28.526
b=(-28-sqrt(844))/2=-14-sqrt(211)=-28.526
b=(-28+sqrt(844))/2=-14+sqrt(211)=0.526
b=(-28+sqrt(844))/2=-14+sqrt(211)=0.526

Step by Step Solution

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Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                (26)/(b+5)-(1+((3)/b-2))=0 

Step by step solution :

Step  1  :

            3
 Simplify   —
            b

Equation at the end of step  1  :

     26             3    
  ——————— -  (1 +  (— -  2))  = 0 
  (b + 5)           b    

Step  2  :

Rewriting the whole as an Equivalent Fraction :

 2.1   Subtracting a whole from a fraction

Rewrite the whole as a fraction using  b  as the denominator :

         2     2 • b
    2 =  —  =  —————
         1       b  

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

 2.2       Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

 3 - (2 • b)     3 - 2b
 ———————————  =  ——————
      b            b   

Equation at the end of step  2  :

     26            (3 - 2b)
  ——————— -  (1 +  ————————)  = 0 
  (b + 5)             b    

Step  3  :

Rewriting the whole as an Equivalent Fraction :

 3.1   Adding a fraction to a whole

Rewrite the whole as a fraction using  b  as the denominator :

          1     1 • b
     1 =  —  =  —————
          1       b  

Adding fractions that have a common denominator :

 3.2       Adding up the two equivalent fractions

 b + (3-2b)     3 - b
 ——————————  =  —————
     b            b  

Equation at the end of step  3  :

     26      (3 - b)
  ——————— -  ———————  = 0 
  (b + 5)       b   

Step  4  :

              26 
 Simplify   —————
            b + 5

Equation at the end of step  4  :

    26     (3 - b)
  ————— -  ———————  = 0 
  b + 5       b   

Step  5  :

Calculating the Least Common Multiple :

 5.1    Find the Least Common Multiple

      The left denominator is :       b+5 

      The right denominator is :       b 

                  Number of times each Algebraic Factor
            appears in the factorization of:
    Algebraic    
    Factor    
 Left 
 Denominator 
 Right 
 Denominator 
 L.C.M = Max 
 {Left,Right} 
 b 011
 b+5 101


      Least Common Multiple:
      b • (b+5) 

Calculating Multipliers :

 5.2    Calculate multipliers for the two fractions


    Denote the Least Common Multiple by  L.C.M 
    Denote the Left Multiplier by  Left_M 
    Denote the Right Multiplier by  Right_M 
    Denote the Left Deniminator by  L_Deno 
    Denote the Right Multiplier by  R_Deno 

   Left_M = L.C.M / L_Deno = b

   Right_M = L.C.M / R_Deno = b+5

Making Equivalent Fractions :

 5.3      Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

   L. Mult. • L. Num.        26 • b 
   ——————————————————  =   —————————
         L.C.M             b • (b+5)

   R. Mult. • R. Num.      (3-b) • (b+5)
   ——————————————————  =   —————————————
         L.C.M               b • (b+5)  

Adding fractions that have a common denominator :

 5.4       Adding up the two equivalent fractions

 26 • b - ((3-b) • (b+5))     b2 + 28b - 15
 ————————————————————————  =  —————————————
        b • (b+5)              b • (b + 5) 

Trying to factor by splitting the middle term

 5.5     Factoring  b2 + 28b - 15 

The first term is,  b2  its coefficient is  1 .
The middle term is,  +28b  its coefficient is  28 .
The last term, "the constant", is  -15 

Step-1 : Multiply the coefficient of the first term by the constant   1 • -15 = -15 

Step-2 : Find two factors of  -15  whose sum equals the coefficient of the middle term, which is   28 .

     -15   +   1   =   -14
     -5   +   3   =   -2
     -3   +   5   =   2
     -1   +   15   =   14


Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored

Equation at the end of step  5  :

  b2 + 28b - 15
  —————————————  = 0 
   b • (b + 5) 

Step  6  :

When a fraction equals zero :

 6.1    When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

  b2+28b-15
  ————————— • b•(b+5) = 0 • b•(b+5)
   b•(b+5) 

Now, on the left hand side, the  b • b+5  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :
   b2+28b-15  = 0

Parabola, Finding the Vertex :

 6.2      Find the Vertex of   y = b2+28b-15

Parabolas have a highest or a lowest point called the Vertex .   Our parabola opens up and accordingly has a lowest point (AKA absolute minimum) .   We know this even before plotting  "y"  because the coefficient of the first term, 1 , is positive (greater than zero). 

 
Each parabola has a vertical line of symmetry that passes through its vertex. Because of this symmetry, the line of symmetry would, for example, pass through the midpoint of the two  x -intercepts (roots or solutions) of the parabola. That is, if the parabola has indeed two real solutions. 

 
Parabolas can model many real life situations, such as the height above ground, of an object thrown upward, after some period of time. The vertex of the parabola can provide us with information, such as the maximum height that object, thrown upwards, can reach. For this reason we want to be able to find the coordinates of the vertex. 

 
For any parabola,Ab2+Bb+C,the  b -coordinate of the vertex is given by  -B/(2A) . In our case the  b  coordinate is  -14.0000  

 
Plugging into the parabola formula  -14.0000  for  b  we can calculate the  y -coordinate : 
 
 y = 1.0 * -14.00 * -14.00 + 28.0 * -14.00 - 15.0
or   y = -211.000

Parabola, Graphing Vertex and X-Intercepts :

Root plot for :  y = b2+28b-15
Axis of Symmetry (dashed)  {b}={-14.00} 
Vertex at  {b,y} = {-14.00,-211.00} 
 b -Intercepts (Roots) :
Root 1 at  {b,y} = {-28.53, 0.00} 
Root 2 at  {b,y} = { 0.53, 0.00} 

Solve Quadratic Equation by Completing The Square

 6.3     Solving   b2+28b-15 = 0 by Completing The Square .

 
Add  15  to both side of the equation :
   b2+28b = 15

Now the clever bit: Take the coefficient of  b , which is  28 , divide by two, giving  14 , and finally square it giving  196 

Add  196  to both sides of the equation :
  On the right hand side we have :
   15  +  196    or,  (15/1)+(196/1) 
  The common denominator of the two fractions is  1   Adding  (15/1)+(196/1)  gives  211/1 
  So adding to both sides we finally get :
   b2+28b+196 = 211

Adding  196  has completed the left hand side into a perfect square :
   b2+28b+196  =
   (b+14) • (b+14)  =
  (b+14)2
Things which are equal to the same thing are also equal to one another. Since
   b2+28b+196 = 211 and
   b2+28b+196 = (b+14)2
then, according to the law of transitivity,
   (b+14)2 = 211

We'll refer to this Equation as  Eq. #6.3.1  

The Square Root Principle says that When two things are equal, their square roots are equal.

Note that the square root of
   (b+14)2   is
   (b+14)2/2 =
  (b+14)1 =
   b+14


Now, applying the Square Root Principle to  Eq. #6.3.1  we get:
   b+14 = 211

Subtract  14  from both sides to obtain:
   b = -14 + √ 211

Since a square root has two values, one positive and the other negative
   b2 + 28b - 15 = 0
   has two solutions:
  b = -14 + √ 211
   or
  b = -14 - √ 211

Solve Quadratic Equation using the Quadratic Formula

 6.4     Solving    b2+28b-15 = 0 by the Quadratic Formula .

 
According to the Quadratic Formula,  b  , the solution for   Ab2+Bb+C  = 0  , where  A, B  and  C  are numbers, often called coefficients, is given by :
                                     
            - B  ±  √ B2-4AC
  b =   ————————
                      2A

  In our case,  A   =     1
                      B   =    28
                      C   =  -15

Accordingly,  B2  -  4AC   =
                     784 - (-60) =
                     844

Applying the quadratic formula :

               -28 ± √ 844
   b  =    ——————
                      2

Can  √ 844 be simplified ?

Yes!   The prime factorization of  844   is
   2•2•211 
To be able to remove something from under the radical, there have to be  2  instances of it (because we are taking a square i.e. second root).

844   =  √ 2•2•211   =
                ±  2 • √ 211


  √ 211   , rounded to 4 decimal digits, is  14.5258
 So now we are looking at:
           b  =  ( -28 ± 2 •  14.526 ) / 2

Two real solutions:

 b =(-28+√844)/2=-14+√ 211 = 0.526

or:

 b =(-28-√844)/2=-14-√ 211 = -28.526

Two solutions were found :

  1.  b =(-28-√844)/2=-14-√ 211 = -28.526
  2.  b =(-28+√844)/2=-14+√ 211 = 0.526

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