Solution - Finding the roots of polynomials
Other Ways to Solve
Finding the roots of polynomialsStep by Step Solution
Step 1 :
5
Simplify —
x
Equation at the end of step 1 :
5 ((((5•(x3))+(21•(x2)))-21x)-—)+5 xStep 2 :
Equation at the end of step 2 :
5 ((((5•(x3))+(3•7x2))-21x)-—)+5 xStep 3 :
Equation at the end of step 3 :
5
(((5x3 + (3•7x2)) - 21x) - —) + 5
x
Step 4 :
Rewriting the whole as an Equivalent Fraction :
4.1 Subtracting a fraction from a whole
Rewrite the whole as a fraction using x as the denominator :
5x3 + 21x2 - 21x (5x3 + 21x2 - 21x) • x
5x3 + 21x2 - 21x = ———————————————— = ——————————————————————
1 x
Equivalent fraction : The fraction thus generated looks different but has the same value as the whole
Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator
Step 5 :
Pulling out like terms :
5.1 Pull out like factors :
5x3 + 21x2 - 21x = x • (5x2 + 21x - 21)
Trying to factor by splitting the middle term
5.2 Factoring 5x2 + 21x - 21
The first term is, 5x2 its coefficient is 5 .
The middle term is, +21x its coefficient is 21 .
The last term, "the constant", is -21
Step-1 : Multiply the coefficient of the first term by the constant 5 • -21 = -105
Step-2 : Find two factors of -105 whose sum equals the coefficient of the middle term, which is 21 .
| -105 | + | 1 | = | -104 | ||
| -35 | + | 3 | = | -32 | ||
| -21 | + | 5 | = | -16 | ||
| -15 | + | 7 | = | -8 | ||
| -7 | + | 15 | = | 8 | ||
| -5 | + | 21 | = | 16 | ||
| -3 | + | 35 | = | 32 | ||
| -1 | + | 105 | = | 104 |
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Adding fractions that have a common denominator :
5.3 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
x • (5x2+21x-21) • x - (5) 5x4 + 21x3 - 21x2 - 5
—————————————————————————— = —————————————————————
x x
Equation at the end of step 5 :
(5x4 + 21x3 - 21x2 - 5)
——————————————————————— + 5
x
Step 6 :
Rewriting the whole as an Equivalent Fraction :
6.1 Adding a whole to a fraction
Rewrite the whole as a fraction using x as the denominator :
5 5 • x
5 = — = —————
1 x
Checking for a perfect cube :
6.2 5x4 + 21x3 - 21x2 - 5 is not a perfect cube
Trying to factor by pulling out :
6.3 Factoring: 5x4 + 21x3 - 21x2 - 5
Thoughtfully split the expression at hand into groups, each group having two terms :
Group 1: 5x4 - 5
Group 2: 21x3 - 21x2
Pull out from each group separately :
Group 1: (x4 - 1) • (5)
Group 2: (x - 1) • (21x2)
Bad news !! Factoring by pulling out fails :
The groups have no common factor and can not be added up to form a multiplication.
Polynomial Roots Calculator :
6.4 Find roots (zeroes) of : F(x) = 5x4 + 21x3 - 21x2 - 5
Polynomial Roots Calculator is a set of methods aimed at finding values of x for which F(x)=0
Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers x which can be expressed as the quotient of two integers
The Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading Coefficient
In this case, the Leading Coefficient is 5 and the Trailing Constant is -5.
The factor(s) are:
of the Leading Coefficient : 1,5
of the Trailing Constant : 1 ,5
Let us test ....
| P | Q | P/Q | F(P/Q) | Divisor | |||||
|---|---|---|---|---|---|---|---|---|---|
| -1 | 1 | -1.00 | -42.00 | ||||||
| -1 | 5 | -0.20 | -6.00 | ||||||
| -5 | 1 | -5.00 | -30.00 | ||||||
| 1 | 1 | 1.00 | 0.00 | x - 1 | |||||
| 1 | 5 | 0.20 | -5.66 | ||||||
| 5 | 1 | 5.00 | 5220.00 |
The Factor Theorem states that if P/Q is root of a polynomial then this polynomial can be divided by q*x-p Note that q and p originate from P/Q reduced to its lowest terms
In our case this means that
5x4 + 21x3 - 21x2 - 5
can be divided with x - 1
Polynomial Long Division :
6.5 Polynomial Long Division
Dividing : 5x4 + 21x3 - 21x2 - 5
("Dividend")
By : x - 1 ("Divisor")
| dividend | 5x4 | + | 21x3 | - | 21x2 | - | 5 | ||||
| - divisor | * 5x3 | 5x4 | - | 5x3 | |||||||
| remainder | 26x3 | - | 21x2 | - | 5 | ||||||
| - divisor | * 26x2 | 26x3 | - | 26x2 | |||||||
| remainder | 5x2 | - | 5 | ||||||||
| - divisor | * 5x1 | 5x2 | - | 5x | |||||||
| remainder | 5x | - | 5 | ||||||||
| - divisor | * 5x0 | 5x | - | 5 | |||||||
| remainder | 0 |
Quotient : 5x3+26x2+5x+5 Remainder: 0
Polynomial Roots Calculator :
6.6 Find roots (zeroes) of : F(x) = 5x3+26x2+5x+5
See theory in step 6.4
In this case, the Leading Coefficient is 5 and the Trailing Constant is 5.
The factor(s) are:
of the Leading Coefficient : 1,5
of the Trailing Constant : 1 ,5
Let us test ....
| P | Q | P/Q | F(P/Q) | Divisor | |||||
|---|---|---|---|---|---|---|---|---|---|
| -1 | 1 | -1.00 | 21.00 | ||||||
| -1 | 5 | -0.20 | 5.00 | ||||||
| -5 | 1 | -5.00 | 5.00 | ||||||
| 1 | 1 | 1.00 | 41.00 | ||||||
| 1 | 5 | 0.20 | 7.08 | ||||||
| 5 | 1 | 5.00 | 1305.00 |
Polynomial Roots Calculator found no rational roots
Adding fractions that have a common denominator :
6.7 Adding up the two equivalent fractions
(5x3+26x2+5x+5) • (x-1) + 5 • x 5x4 + 21x3 - 21x2 + 5x - 5
——————————————————————————————— = ——————————————————————————
x x
Polynomial Roots Calculator :
6.8 Find roots (zeroes) of : F(x) = 5x4 + 21x3 - 21x2 + 5x - 5
See theory in step 6.4
In this case, the Leading Coefficient is 5 and the Trailing Constant is -5.
The factor(s) are:
of the Leading Coefficient : 1,5
of the Trailing Constant : 1 ,5
Let us test ....
| P | Q | P/Q | F(P/Q) | Divisor | |||||
|---|---|---|---|---|---|---|---|---|---|
| -1 | 1 | -1.00 | -47.00 | ||||||
| -1 | 5 | -0.20 | -7.00 | ||||||
| -5 | 1 | -5.00 | -55.00 | ||||||
| 1 | 1 | 1.00 | 5.00 | ||||||
| 1 | 5 | 0.20 | -4.66 | ||||||
| 5 | 1 | 5.00 | 5245.00 |
Polynomial Roots Calculator found no rational roots
Final result :
5x4 + 21x3 21x2 + 5x - 5
——————————————————————————
x
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