Solution - Simplification or other simple results
7x^2-5x+4
Step by Step Solution
Step 1 :
Equation at the end of step 1 :
(((0-(6•(x2)))+4)+13x2)-5xStep 2 :
Equation at the end of step 2 :
(((0 - (2•3x2)) + 4) + 13x2) - 5x
Step 3 :
Trying to factor by splitting the middle term
3.1 Factoring 7x2-5x+4
The first term is, 7x2 its coefficient is 7 .
The middle term is, -5x its coefficient is -5 .
The last term, "the constant", is +4
Step-1 : Multiply the coefficient of the first term by the constant 7 • 4 = 28
Step-2 : Find two factors of 28 whose sum equals the coefficient of the middle term, which is -5 .
-28 | + | -1 | = | -29 | ||
-14 | + | -2 | = | -16 | ||
-7 | + | -4 | = | -11 | ||
-4 | + | -7 | = | -11 | ||
-2 | + | -14 | = | -16 | ||
-1 | + | -28 | = | -29 | ||
1 | + | 28 | = | 29 | ||
2 | + | 14 | = | 16 | ||
4 | + | 7 | = | 11 | ||
7 | + | 4 | = | 11 | ||
14 | + | 2 | = | 16 | ||
28 | + | 1 | = | 29 |
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Final result :
7x2 - 5x + 4
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