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Solution - Simplification or other simple results

(5y)(y2+5y+25)
(5-y)*(y^2+5y+25)

Step by Step Solution

Reformatting the input :

Changes made to your input should not affect the solution:

 (1): "y3"   was replaced by   "y^3". 

Step  1  :

Trying to factor as a Difference of Cubes:

 1.1      Factoring:  125-y3 

Theory : A difference of two perfect cubes,  a3 - b3 can be factored into
              (a-b) • (a2 +ab +b2)

Proof :  (a-b)•(a2+ab+b2) =
            a3+a2b+ab2-ba2-b2a-b3 =
            a3+(a2b-ba2)+(ab2-b2a)-b3 =
            a3+0+0-b3 =
            a3-b3


Check :  125  is the cube of  5 

Check :  y3 is the cube of   y1

Factorization is :
             (5 - y)  •  (25 + 5y + y2) 

Trying to factor by splitting the middle term

 1.2     Factoring  y2 + 5y + 25 

The first term is,  y2  its coefficient is  1 .
The middle term is,  +5y  its coefficient is  5 .
The last term, "the constant", is  +25 

Step-1 : Multiply the coefficient of the first term by the constant   1 • 25 = 25 

Step-2 : Find two factors of  25  whose sum equals the coefficient of the middle term, which is   5 .

     -25   +   -1   =   -26
     -5   +   -5   =   -10
     -1   +   -25   =   -26
     1   +   25   =   26
     5   +   5   =   10
     25   +   1   =   26


Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored

Final result :

  (5 - y) • (y2 + 5y + 25)

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