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Solution - Simplification or other simple results

2(5x4)(25x2+20x+16)
-2*(5x-4)*(25x^2+20x+16)

Step by Step Solution

Reformatting the input :

Changes made to your input should not affect the solution:

 (1): "x3"   was replaced by   "x^3". 

Step  1  :

Equation at the end of step  1  :

  128 -  (2•53x3)

Step  2  :

Step  3  :

Pulling out like terms :

 3.1     Pull out like factors :

   128 - 250x3  =   -2 • (125x3 - 64) 

Trying to factor as a Difference of Cubes:

 3.2      Factoring:  125x3 - 64 

Theory : A difference of two perfect cubes,  a3 - b3 can be factored into
              (a-b) • (a2 +ab +b2)

Proof :  (a-b)•(a2+ab+b2) =
            a3+a2b+ab2-ba2-b2a-b3 =
            a3+(a2b-ba2)+(ab2-b2a)-b3 =
            a3+0+0-b3 =
            a3-b3


Check :  125  is the cube of  5 

Check :  64  is the cube of   4 
Check :  x3 is the cube of   x1

Factorization is :
             (5x - 4)  •  (25x2 + 20x + 16) 

Trying to factor by splitting the middle term

 3.3     Factoring  25x2 + 20x + 16 

The first term is,  25x2  its coefficient is  25 .
The middle term is,  +20x  its coefficient is  20 .
The last term, "the constant", is  +16 

Step-1 : Multiply the coefficient of the first term by the constant   25 • 16 = 400 

Step-2 : Find two factors of  400  whose sum equals the coefficient of the middle term, which is   20 .

     -400   +   -1   =   -401
     -200   +   -2   =   -202
     -100   +   -4   =   -104
     -80   +   -5   =   -85
     -50   +   -8   =   -58
     -40   +   -10   =   -50


For tidiness, printing of 24 lines which failed to find two such factors, was suppressed

Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored

Final result :

  -2 • (5x - 4) • (25x2 + 20x + 16)

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