Adding, subtracting and finding the least common multiple
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This solution deals with adding, subtracting and finding the least common multiple.
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- Adding, subtracting and finding the least common multiple
Step by Step Solution
Reformatting the input :
Changes made to your input should not affect the solution:
(1): "/-4h" was replaced by "/(-4h)".
Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
21/(-4*h)-(14/11+h)=0
Step by step solution :
Step 1 :
14
Simplify ——
11
Equation at the end of step 1 :
21 14
——— - (—— + h) = 0
-4h 11
Step 2 :
Rewriting the whole as an Equivalent Fraction :
2.1 Adding a whole to a fraction
Rewrite the whole as a fraction using 11 as the denominator :
h h • 11
h = — = ——————
1 11
Equivalent fraction : The fraction thus generated looks different but has the same value as the whole
Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator
Adding fractions that have a common denominator :
2.2 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
14 + h • 11 11h + 14
——————————— = ————————
11 11
Equation at the end of step 2 :
21 (11h + 14)
——— - —————————— = 0
-4h 11
Step 3 :
21
Simplify ———
-4h
Equation at the end of step 3 :
21 (11h + 14)
——— - —————————— = 0
-4h 11
Step 4 :
Calculating the Least Common Multiple :
4.1 Find the Least Common Multiple
The left denominator is : -4h
The right denominator is : 11
Prime Factor | Left Denominator | Right Denominator | L.C.M = Max {Left,Right} |
---|---|---|---|
2 | 2 | 0 | 2 |
11 | 0 | 1 | 1 |
Product of all Prime Factors | -4 | 11 | 44 |
Algebraic Factor | Left Denominator | Right Denominator | L.C.M = Max {Left,Right} |
---|---|---|---|
h | 1 | 0 | 1 |
Least Common Multiple:
44h
Calculating Multipliers :
4.2 Calculate multipliers for the two fractions
Denote the Least Common Multiple by L.C.M
Denote the Left Multiplier by Left_M
Denote the Right Multiplier by Right_M
Denote the Left Deniminator by L_Deno
Denote the Right Multiplier by R_Deno
Left_M = L.C.M / L_Deno = -11
Right_M = L.C.M / R_Deno = 4h
Making Equivalent Fractions :
4.3 Rewrite the two fractions into equivalent fractions
Two fractions are called equivalent if they have the same numeric value.
For example : 1/2 and 2/4 are equivalent, y/(y+1)2 and (y2+y)/(y+1)3 are equivalent as well.
To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.
L. Mult. • L. Num. 21 • -11 —————————————————— = ———————— L.C.M 44h R. Mult. • R. Num. (11h+14) • 4h —————————————————— = ————————————— L.C.M 44h
Adding fractions that have a common denominator :
4.4 Adding up the two equivalent fractions
21 • -11 - ((11h+14) • 4h) -44h2 - 56h - 231
—————————————————————————— = —————————————————
44h 44h
Step 5 :
Pulling out like terms :
5.1 Pull out like factors :
-44h2 - 56h - 231 = -1 • (44h2 + 56h + 231)
Trying to factor by splitting the middle term
5.2 Factoring 44h2 + 56h + 231
The first term is, 44h2 its coefficient is 44 .
The middle term is, +56h its coefficient is 56 .
The last term, "the constant", is +231
Step-1 : Multiply the coefficient of the first term by the constant 44 • 231 = 10164
Step-2 : Find two factors of 10164 whose sum equals the coefficient of the middle term, which is 56 .
-10164 | + | -1 | = | -10165 | ||
-5082 | + | -2 | = | -5084 | ||
-3388 | + | -3 | = | -3391 | ||
-2541 | + | -4 | = | -2545 | ||
-1694 | + | -6 | = | -1700 | ||
-1452 | + | -7 | = | -1459 |
For tidiness, printing of 66 lines which failed to find two such factors, was suppressed
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Equation at the end of step 5 :
-44h2 - 56h - 231
————————————————— = 0
44h
Step 6 :
When a fraction equals zero :
6.1 When a fraction equals zero ...
Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.
Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.
Here's how:
-44h2-56h-231
————————————— • 44h = 0 • 44h
44h
Now, on the left hand side, the 44h cancels out the denominator, while, on the right hand side, zero times anything is still zero.
The equation now takes the shape :
-44h2-56h-231 = 0
Parabola, Finding the Vertex :
6.2 Find the Vertex of y = -44h2-56h-231
Parabolas have a highest or a lowest point called the Vertex . Our parabola opens down and accordingly has a highest point (AKA absolute maximum) . We know this even before plotting "y" because the coefficient of the first term, -44 , is negative (smaller than zero).
Each parabola has a vertical line of symmetry that passes through its vertex. Because of this symmetry, the line of symmetry would, for example, pass through the midpoint of the two x -intercepts (roots or solutions) of the parabola. That is, if the parabola has indeed two real solutions.
Parabolas can model many real life situations, such as the height above ground, of an object thrown upward, after some period of time. The vertex of the parabola can provide us with information, such as the maximum height that object, thrown upwards, can reach. For this reason we want to be able to find the coordinates of the vertex.
For any parabola,Ah2+Bh+C,the h -coordinate of the vertex is given by -B/(2A) . In our case the h coordinate is -0.6364
Plugging into the parabola formula -0.6364 for h we can calculate the y -coordinate :
y = -44.0 * -0.64 * -0.64 - 56.0 * -0.64 - 231.0
or y = -213.182
Parabola, Graphing Vertex and X-Intercepts :
Root plot for : y = -44h2-56h-231
Axis of Symmetry (dashed) {h}={-0.64}
Vertex at {h,y} = {-0.64,-213.18}
Function has no real roots
Solve Quadratic Equation by Completing The Square
6.3 Solving -44h2-56h-231 = 0 by Completing The Square .
Multiply both sides of the equation by (-1) to obtain positive coefficient for the first term:
44h2+56h+231 = 0 Divide both sides of the equation by 44 to have 1 as the coefficient of the first term :
h2+(14/11)h+(21/4) = 0
Subtract 21/4 from both side of the equation :
h2+(14/11)h = -21/4
Now the clever bit: Take the coefficient of h , which is 14/11 , divide by two, giving 7/11 , and finally square it giving 49/121
Add 49/121 to both sides of the equation :
On the right hand side we have :
-21/4 + 49/121 The common denominator of the two fractions is 484 Adding (-2541/484)+(196/484) gives -2345/484
So adding to both sides we finally get :
h2+(14/11)h+(49/121) = -2345/484
Adding 49/121 has completed the left hand side into a perfect square :
h2+(14/11)h+(49/121) =
(h+(7/11)) • (h+(7/11)) =
(h+(7/11))2
Things which are equal to the same thing are also equal to one another. Since
h2+(14/11)h+(49/121) = -2345/484 and
h2+(14/11)h+(49/121) = (h+(7/11))2
then, according to the law of transitivity,
(h+(7/11))2 = -2345/484
We'll refer to this Equation as Eq. #6.3.1
The Square Root Principle says that When two things are equal, their square roots are equal.
Note that the square root of
(h+(7/11))2 is
(h+(7/11))2/2 =
(h+(7/11))1 =
h+(7/11)
Now, applying the Square Root Principle to Eq. #6.3.1 we get:
h+(7/11) = √ -2345/484
Subtract 7/11 from both sides to obtain:
h = -7/11 + √ -2345/484
In Math, i is called the imaginary unit. It satisfies i2 =-1. Both i and -i are the square roots of -1
Since a square root has two values, one positive and the other negative
h2 + (14/11)h + (21/4) = 0
has two solutions:
h = -7/11 + √ 2345/484 • i
or
h = -7/11 - √ 2345/484 • i
Note that √ 2345/484 can be written as
√ 2345 / √ 484 which is √ 2345 / 22
Solve Quadratic Equation using the Quadratic Formula
6.4 Solving -44h2-56h-231 = 0 by the Quadratic Formula .
According to the Quadratic Formula, h , the solution for Ah2+Bh+C = 0 , where A, B and C are numbers, often called coefficients, is given by :
- B ± √ B2-4AC
h = ————————
2A
In our case, A = -44
B = -56
C = -231
Accordingly, B2 - 4AC =
3136 - 40656 =
-37520
Applying the quadratic formula :
56 ± √ -37520
h = ————————
-88
In the set of real numbers, negative numbers do not have square roots. A new set of numbers, called complex, was invented so that negative numbers would have a square root. These numbers are written (a+b*i)
Both i and -i are the square roots of minus 1
Accordingly,√ -37520 =
√ 37520 • (-1) =
√ 37520 • √ -1 =
± √ 37520 • i
Can √ 37520 be simplified ?
Yes! The prime factorization of 37520 is
2•2•2•2•5•7•67
To be able to remove something from under the radical, there have to be 2 instances of it (because we are taking a square i.e. second root).
√ 37520 = √ 2•2•2•2•5•7•67 =2•2•√ 2345 =
± 4 • √ 2345
√ 2345 , rounded to 4 decimal digits, is 48.4252
So now we are looking at:
h = ( 56 ± 4 • 48.425 i ) / -88
Two imaginary solutions :
h =(56+√-37520)/-88=7/-11-i/22√ 2345 = -0.6364+2.2011i or:
h =(56-√-37520)/-88=7/-11+i/22√ 2345 = -0.6364-2.2011i
Two solutions were found :
- h =(56-√-37520)/-88=7/-11+i/22√ 2345 = -0.6364-2.2011i
- h =(56+√-37520)/-88=7/-11-i/22√ 2345 = -0.6364+2.2011i