Solution - Nonlinear equations
Step by Step Solution
Step by step solution :
Step 1 :
Equation at the end of step 1 :
22 + (22•3x2) = 0
Step 2 :
Step 3 :
Pulling out like terms :
3.1 Pull out like factors :
12x2 + 22 = 2 • (6x2 + 11)
Polynomial Roots Calculator :
3.2 Find roots (zeroes) of : F(x) = 6x2 + 11
Polynomial Roots Calculator is a set of methods aimed at finding values of x for which F(x)=0
Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers x which can be expressed as the quotient of two integers
The Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading Coefficient
In this case, the Leading Coefficient is 6 and the Trailing Constant is 11.
The factor(s) are:
of the Leading Coefficient : 1,2 ,3 ,6
of the Trailing Constant : 1 ,11
Let us test ....
| P | Q | P/Q | F(P/Q) | Divisor | |||||
|---|---|---|---|---|---|---|---|---|---|
| -1 | 1 | -1.00 | 17.00 | ||||||
| -1 | 2 | -0.50 | 12.50 | ||||||
| -1 | 3 | -0.33 | 11.67 | ||||||
| -1 | 6 | -0.17 | 11.17 | ||||||
| -11 | 1 | -11.00 | 737.00 | ||||||
| -11 | 2 | -5.50 | 192.50 | ||||||
| -11 | 3 | -3.67 | 91.67 | ||||||
| -11 | 6 | -1.83 | 31.17 | ||||||
| 1 | 1 | 1.00 | 17.00 | ||||||
| 1 | 2 | 0.50 | 12.50 | ||||||
| 1 | 3 | 0.33 | 11.67 | ||||||
| 1 | 6 | 0.17 | 11.17 | ||||||
| 11 | 1 | 11.00 | 737.00 | ||||||
| 11 | 2 | 5.50 | 192.50 | ||||||
| 11 | 3 | 3.67 | 91.67 | ||||||
| 11 | 6 | 1.83 | 31.17 |
Polynomial Roots Calculator found no rational roots
Equation at the end of step 3 :
2 • (6x2 + 11) = 0
Step 4 :
Equations which are never true :
4.1 Solve : 2 = 0
This equation has no solution.
A a non-zero constant never equals zero.
Solving a Single Variable Equation :
4.2 Solve : 6x2+11 = 0
Subtract 11 from both sides of the equation :
6x2 = -11
Divide both sides of the equation by 6:
x2 = -11/6 = -1.833
When two things are equal, their square roots are equal. Taking the square root of the two sides of the equation we get:
x = ± √ -11/6
In Math, i is called the imaginary unit. It satisfies i2 =-1. Both i and -i are the square roots of -1
Accordingly, √ -11/6 =
√ -1• 11/6 =
√ -1 •√ 11/6 =
i • √ 11/6
The equation has no real solutions. It has 2 imaginary, or complex solutions.
x= 0.0000 + 1.3540 i
x= 0.0000 - 1.3540 i
Two solutions were found :
- x= 0.0000 - 1.3540 i
- x= 0.0000 + 1.3540 i
How did we do?
Please leave us feedback.