Solution - Reducing fractions to their lowest terms
Other Ways to Solve
Reducing fractions to their lowest termsStep by Step Solution
Step 1 :
40
Simplify ——
y
Equation at the end of step 1 :
40 (((2 • (y2)) + 3y) - ——) + 5 yStep 2 :
Equation at the end of step 2 :
40
((2y2 + 3y) - ——) + 5
y
Step 3 :
Rewriting the whole as an Equivalent Fraction :
3.1 Subtracting a fraction from a whole
Rewrite the whole as a fraction using y as the denominator :
2y2 + 3y (2y2 + 3y) • y
2y2 + 3y = ———————— = ——————————————
1 y
Equivalent fraction : The fraction thus generated looks different but has the same value as the whole
Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator
Step 4 :
Pulling out like terms :
4.1 Pull out like factors :
2y2 + 3y = y • (2y + 3)
Adding fractions that have a common denominator :
4.2 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
y • (2y+3) • y - (40) 2y3 + 3y2 - 40
————————————————————— = ——————————————
y y
Equation at the end of step 4 :
(2y3 + 3y2 - 40)
———————————————— + 5
y
Step 5 :
Rewriting the whole as an Equivalent Fraction :
5.1 Adding a whole to a fraction
Rewrite the whole as a fraction using y as the denominator :
5 5 • y
5 = — = —————
1 y
Polynomial Roots Calculator :
5.2 Find roots (zeroes) of : F(y) = 2y3 + 3y2 - 40
Polynomial Roots Calculator is a set of methods aimed at finding values of y for which F(y)=0
Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers y which can be expressed as the quotient of two integers
The Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading Coefficient
In this case, the Leading Coefficient is 2 and the Trailing Constant is -40.
The factor(s) are:
of the Leading Coefficient : 1,2
of the Trailing Constant : 1 ,2 ,4 ,5 ,8 ,10 ,20 ,40
Let us test ....
| P | Q | P/Q | F(P/Q) | Divisor | |||||
|---|---|---|---|---|---|---|---|---|---|
| -1 | 1 | -1.00 | -39.00 | ||||||
| -1 | 2 | -0.50 | -39.50 | ||||||
| -2 | 1 | -2.00 | -44.00 | ||||||
| -4 | 1 | -4.00 | -120.00 | ||||||
| -5 | 1 | -5.00 | -215.00 |
Note - For tidiness, printing of 15 checks which found no root was suppressed
Polynomial Roots Calculator found no rational roots
Adding fractions that have a common denominator :
5.3 Adding up the two equivalent fractions
(2y3+3y2-40) + 5 • y 2y3 + 3y2 + 5y - 40
———————————————————— = ———————————————————
y y
Checking for a perfect cube :
5.4 2y3 + 3y2 + 5y - 40 is not a perfect cube
Trying to factor by pulling out :
5.5 Factoring: 2y3 + 3y2 + 5y - 40
Thoughtfully split the expression at hand into groups, each group having two terms :
Group 1: 5y - 40
Group 2: 2y3 + 3y2
Pull out from each group separately :
Group 1: (y - 8) • (5)
Group 2: (2y + 3) • (y2)
Bad news !! Factoring by pulling out fails :
The groups have no common factor and can not be added up to form a multiplication.
Polynomial Roots Calculator :
5.6 Find roots (zeroes) of : F(y) = 2y3 + 3y2 + 5y - 40
See theory in step 5.2
In this case, the Leading Coefficient is 2 and the Trailing Constant is -40.
The factor(s) are:
of the Leading Coefficient : 1,2
of the Trailing Constant : 1 ,2 ,4 ,5 ,8 ,10 ,20 ,40
Let us test ....
| P | Q | P/Q | F(P/Q) | Divisor | |||||
|---|---|---|---|---|---|---|---|---|---|
| -1 | 1 | -1.00 | -44.00 | ||||||
| -1 | 2 | -0.50 | -42.00 | ||||||
| -2 | 1 | -2.00 | -54.00 | ||||||
| -4 | 1 | -4.00 | -140.00 | ||||||
| -5 | 1 | -5.00 | -240.00 |
Note - For tidiness, printing of 15 checks which found no root was suppressed
Polynomial Roots Calculator found no rational roots
Final result :
2y3 + 3y2 + 5y - 40
———————————————————
y
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