Solution - Adding, subtracting and finding the least common multiple
Step by Step Solution
Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : 
                     30/600-(x/150)=0 
Step by step solution :
Step 1 :
             x 
 Simplify   ———
            150
Equation at the end of step 1 :
   30     x 
  ——— -  ———  = 0 
  600    150
Step 2 :
             1
 Simplify   ——
            20
Equation at the end of step 2 :
   1     x 
  —— -  ———  = 0 
  20    150
Step 3 :
Calculating the Least Common Multiple :
 3.1    Find the Least Common Multiple 
 
      The left denominator is :       20 
      The right denominator is :       150 
| Prime Factor | Left Denominator | Right Denominator | L.C.M = Max {Left,Right} | 
|---|---|---|---|
| 2 | 2 | 1 | 2 | 
| 5 | 1 | 2 | 2 | 
| 3 | 0 | 1 | 1 | 
| Product of all Prime Factors | 20 | 150 | 300 | 
      Least Common Multiple: 
      300 
Calculating Multipliers :
 3.2    Calculate multipliers for the two fractions 
    Denote the Least Common Multiple by  L.C.M 
    Denote the Left Multiplier by  Left_M 
    Denote the Right Multiplier by  Right_M 
    Denote the Left Deniminator by  L_Deno 
    Denote the Right Multiplier by  R_Deno 
   Left_M = L.C.M / L_Deno = 15
   Right_M = L.C.M / R_Deno = 2
Making Equivalent Fractions :
 3.3      Rewrite the two fractions into equivalent fractions
Two fractions are called equivalent if they have the same numeric value.
 For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well. 
To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.
L. Mult. • L. Num. 15 —————————————————— = ——— L.C.M 300 R. Mult. • R. Num. x • 2 —————————————————— = ————— L.C.M 300
Adding fractions that have a common denominator :
 3.4       Adding up the two equivalent fractions 
Add the two equivalent fractions which now have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
 15 - (x • 2)     15 - 2x
 ————————————  =  ———————
     300            300  
Equation at the end of step 3 :
  15 - 2x
  ———————  = 0 
    300  
Step 4 :
When a fraction equals zero :
 4.1    When a fraction equals zero ...Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.
Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.
Here's how:
  15-2x
  ————— • 300 = 0 • 300
   300 
Now, on the left hand side, the  300  cancels out the denominator, while, on the right hand side, zero times anything is still zero.
The equation now takes the shape :
   15-2x  = 0
Solving a Single Variable Equation :
 4.2      Solve  :    -2x+15 = 0 
 Subtract  15  from both sides of the equation : 
                      -2x = -15 
Multiply both sides of the equation by (-1) :  2x = 15 
Divide both sides of the equation by 2:
                     x = 15/2 = 7.500 
One solution was found :
x = 15/2 = 7.500How did we do?
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