Solution - Factoring binomials using the difference of squares
Step by Step Solution
Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
36*x^2-(49)=0
Step by step solution :
Step 1 :
Equation at the end of step 1 :
(22•32x2) - 49 = 0
Step 2 :
Trying to factor as a Difference of Squares :
2.1 Factoring: 36x2-49
Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)
Proof : (A+B) • (A-B) =
A2 - AB + BA - B2 =
A2 - AB + AB - B2 =
A2 - B2
Note : AB = BA is the commutative property of multiplication.
Note : - AB + AB equals zero and is therefore eliminated from the expression.
Check : 36 is the square of 6
Check : 49 is the square of 7
Check : x2 is the square of x1
Factorization is : (6x + 7) • (6x - 7)
Equation at the end of step 2 :
(6x + 7) • (6x - 7) = 0
Step 3 :
Theory - Roots of a product :
3.1 A product of several terms equals zero.
When a product of two or more terms equals zero, then at least one of the terms must be zero.
We shall now solve each term = 0 separately
In other words, we are going to solve as many equations as there are terms in the product
Any solution of term = 0 solves product = 0 as well.
Solving a Single Variable Equation :
3.2 Solve : 6x+7 = 0
Subtract 7 from both sides of the equation :
6x = -7
Divide both sides of the equation by 6:
x = -7/6 = -1.167
Solving a Single Variable Equation :
3.3 Solve : 6x-7 = 0
Add 7 to both sides of the equation :
6x = 7
Divide both sides of the equation by 6:
x = 7/6 = 1.167
Two solutions were found :
- x = 7/6 = 1.167
- x = -7/6 = -1.167
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