Solution - Simplification or other simple results
11k^3*(4k^2-6k+7)
Other Ways to Solve
Simplification or other simple resultsStep by Step Solution
Step 1 :
Equation at the end of step 1 :
((44•(k5))-(66•(k4)))+(7•11k3)Step 2 :
Equation at the end of step 2 :
((44 • (k5)) - (2•3•11k4)) + (7•11k3)Step 3 :
Equation at the end of step 3 :
((22•11k5) - (2•3•11k4)) + (7•11k3)
Step 4 :
Step 5 :
Pulling out like terms :
5.1 Pull out like factors :
44k5 - 66k4 + 77k3 = 11k3 • (4k2 - 6k + 7)
Trying to factor by splitting the middle term
5.2 Factoring 4k2 - 6k + 7
The first term is, 4k2 its coefficient is 4 .
The middle term is, -6k its coefficient is -6 .
The last term, "the constant", is +7
Step-1 : Multiply the coefficient of the first term by the constant 4 • 7 = 28
Step-2 : Find two factors of 28 whose sum equals the coefficient of the middle term, which is -6 .
| -28 | + | -1 | = | -29 | ||
| -14 | + | -2 | = | -16 | ||
| -7 | + | -4 | = | -11 | ||
| -4 | + | -7 | = | -11 | ||
| -2 | + | -14 | = | -16 | ||
| -1 | + | -28 | = | -29 | ||
| 1 | + | 28 | = | 29 | ||
| 2 | + | 14 | = | 16 | ||
| 4 | + | 7 | = | 11 | ||
| 7 | + | 4 | = | 11 | ||
| 14 | + | 2 | = | 16 | ||
| 28 | + | 1 | = | 29 |
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Final result :
11k3 • (4k2 - 6k + 7)
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