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Solution - Simplification or other simple results

11k3(4k26k+7)
11k^3*(4k^2-6k+7)

Step by Step Solution

Step  1  :

Equation at the end of step  1  :

  ((44•(k5))-(66•(k4)))+(7•11k3)

Step  2  :

Equation at the end of step  2  :

  ((44 • (k5)) -  (2•3•11k4)) +  (7•11k3)

Step  3  :

Equation at the end of step  3  :

  ((22•11k5) -  (2•3•11k4)) +  (7•11k3)

Step  4  :

Step  5  :

Pulling out like terms :

 5.1     Pull out like factors :

   44k5 - 66k4 + 77k3  =   11k3 • (4k2 - 6k + 7) 

Trying to factor by splitting the middle term

 5.2     Factoring  4k2 - 6k + 7 

The first term is,  4k2  its coefficient is  4 .
The middle term is,  -6k  its coefficient is  -6 .
The last term, "the constant", is  +7 

Step-1 : Multiply the coefficient of the first term by the constant   4 • 7 = 28 

Step-2 : Find two factors of  28  whose sum equals the coefficient of the middle term, which is   -6 .

     -28   +   -1   =   -29
     -14   +   -2   =   -16
     -7   +   -4   =   -11
     -4   +   -7   =   -11
     -2   +   -14   =   -16
     -1   +   -28   =   -29
     1   +   28   =   29
     2   +   14   =   16
     4   +   7   =   11
     7   +   4   =   11
     14   +   2   =   16
     28   +   1   =   29


Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored

Final result :

  11k3 • (4k2 - 6k + 7)

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