Solution - Adding, subtracting and finding the least common multiple
Step by Step Solution
Reformatting the input :
Changes made to your input should not affect the solution:
(1): "12.5" was replaced by "(125/10)". 2 more similar replacement(s)
Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
4*t+(35/10)-((125/10))=0
Step by step solution :
Step 1 :
25
Simplify ——
2
Equation at the end of step 1 :
35 25
(4t + ——) - —— = 0
10 2
Step 2 :
7
Simplify —
2
Equation at the end of step 2 :
7 25
(4t + —) - —— = 0
2 2
Step 3 :
Rewriting the whole as an Equivalent Fraction :
3.1 Adding a fraction to a whole
Rewrite the whole as a fraction using 2 as the denominator :
4t 4t • 2
4t = —— = ——————
1 2
Equivalent fraction : The fraction thus generated looks different but has the same value as the whole
Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator
Adding fractions that have a common denominator :
3.2 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
4t • 2 + 7 8t + 7
—————————— = ——————
2 2
Equation at the end of step 3 :
(8t + 7) 25
———————— - —— = 0
2 2
Step 4 :
Adding fractions which have a common denominator :
4.1 Adding fractions which have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
(8t+7) - (25) 8t - 18
————————————— = ———————
2 2
Step 5 :
Pulling out like terms :
5.1 Pull out like factors :
8t - 18 = 2 • (4t - 9)
Equation at the end of step 5 :
4t - 9 = 0
Step 6 :
Solving a Single Variable Equation :
6.1 Solve : 4t-9 = 0
Add 9 to both sides of the equation :
4t = 9
Divide both sides of the equation by 4:
t = 9/4 = 2.250
One solution was found :
t = 9/4 = 2.250How did we do?
Please leave us feedback.