Solution - Reducing fractions to their lowest terms
Other Ways to Solve
Reducing fractions to their lowest termsStep by Step Solution
Step 1 :
12
Simplify ——
7
Equation at the end of step 1 :
12
((4x + (—— • x2)) - 21x) - 126
7
Step 2 :
Equation at the end of step 2 :
12x2
((4x + ————) - 21x) - 126
7
Step 3 :
Rewriting the whole as an Equivalent Fraction :
3.1 Adding a fraction to a whole
Rewrite the whole as a fraction using 7 as the denominator :
4x 4x • 7
4x = —— = ——————
1 7
Equivalent fraction : The fraction thus generated looks different but has the same value as the whole
Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator
Adding fractions that have a common denominator :
3.2 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
4x • 7 + 12x2 12x2 + 28x
————————————— = ——————————
7 7
Equation at the end of step 3 :
(12x2 + 28x)
(———————————— - 21x) - 126
7
Step 4 :
Rewriting the whole as an Equivalent Fraction :
4.1 Subtracting a whole from a fraction
Rewrite the whole as a fraction using 7 as the denominator :
21x 21x • 7
21x = ——— = ———————
1 7
Step 5 :
Pulling out like terms :
5.1 Pull out like factors :
12x2 + 28x = 4x • (3x + 7)
Adding fractions that have a common denominator :
5.2 Adding up the two equivalent fractions
4x • (3x+7) - (21x • 7) 12x2 - 119x
——————————————————————— = ———————————
7 7
Equation at the end of step 5 :
(12x2 - 119x)
————————————— - 126
7
Step 6 :
Rewriting the whole as an Equivalent Fraction :
6.1 Subtracting a whole from a fraction
Rewrite the whole as a fraction using 7 as the denominator :
126 126 • 7
126 = ——— = ———————
1 7
Step 7 :
Pulling out like terms :
7.1 Pull out like factors :
12x2 - 119x = x • (12x - 119)
Adding fractions that have a common denominator :
7.2 Adding up the two equivalent fractions
x • (12x-119) - (126 • 7) 12x2 - 119x - 882
————————————————————————— = —————————————————
7 7
Trying to factor by splitting the middle term
7.3 Factoring 12x2 - 119x - 882
The first term is, 12x2 its coefficient is 12 .
The middle term is, -119x its coefficient is -119 .
The last term, "the constant", is -882
Step-1 : Multiply the coefficient of the first term by the constant 12 • -882 = -10584
Step-2 : Find two factors of -10584 whose sum equals the coefficient of the middle term, which is -119 .
| -10584 | + | 1 | = | -10583 | ||
| -5292 | + | 2 | = | -5290 | ||
| -3528 | + | 3 | = | -3525 | ||
| -2646 | + | 4 | = | -2642 | ||
| -1764 | + | 6 | = | -1758 | ||
| -1512 | + | 7 | = | -1505 |
For tidiness, printing of 42 lines which failed to find two such factors, was suppressed
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Final result :
12x2 - 119x - 882
—————————————————
7
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