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Solution - Equations reducible to quadratic form

x=0.00000.5000i
x=0.0000-0.5000i
x=0.0000+0.5000i
x=0.0000+0.5000i
x=±(3)=±1.7321
x=±sqrt(3)=±1.7321

Step by Step Solution

Step by step solution :

Step  1  :

Equation at the end of step  1  :

  ((4 • (x4)) -  11x2) -  3  = 0 

Step  2  :

Equation at the end of step  2  :

  (22x4 -  11x2) -  3  = 0 

Step  3  :

Trying to factor by splitting the middle term

 3.1     Factoring  4x4-11x2-3 

The first term is,  4x4  its coefficient is  4 .
The middle term is,  -11x2  its coefficient is  -11 .
The last term, "the constant", is  -3 

Step-1 : Multiply the coefficient of the first term by the constant   4 • -3 = -12 

Step-2 : Find two factors of  -12  whose sum equals the coefficient of the middle term, which is   -11 .

     -12   +   1   =   -11   That's it


Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -12  and  1 
                     4x4 - 12x2 + 1x2 - 3

Step-4 : Add up the first 2 terms, pulling out like factors :
                    4x2 • (x2-3)
              Add up the last 2 terms, pulling out common factors :
                     1 • (x2-3)
Step-5 : Add up the four terms of step 4 :
                    (4x2+1)  •  (x2-3)
             Which is the desired factorization

Trying to factor as a Difference of Squares :

 3.2      Factoring:  x2-3 

Theory : A difference of two perfect squares,  A2 - B2  can be factored into  (A+B) • (A-B)

Proof :  (A+B) • (A-B) =
         A2 - AB + BA - B2 =
         A2 - AB + AB - B2 =
         A2 - B2

Note :  AB = BA is the commutative property of multiplication.

Note :  - AB + AB equals zero and is therefore eliminated from the expression.

Check : 3 is not a square !!

Ruling : Binomial can not be factored as the difference of two perfect squares.

Polynomial Roots Calculator :

 3.3    Find roots (zeroes) of :       F(x) = 4x2+1
Polynomial Roots Calculator is a set of methods aimed at finding values of  x  for which   F(x)=0  

Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers  x  which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number  P/Q   then  P  is a factor of the Trailing Constant and  Q  is a factor of the Leading Coefficient

In this case, the Leading Coefficient is  4  and the Trailing Constant is  1.

 
The factor(s) are:

of the Leading Coefficient :  1,2 ,4
 
of the Trailing Constant :  1

 
Let us test ....

  P  Q  P/Q  F(P/Q)   Divisor
     -1     1      -1.00      5.00   
     -1     2      -0.50      2.00   
     -1     4      -0.25      1.25   
     1     1      1.00      5.00   
     1     2      0.50      2.00   
     1     4      0.25      1.25   


Polynomial Roots Calculator found no rational roots

Equation at the end of step  3  :

  (x2 - 3) • (4x2 + 1)  = 0 

Step  4  :

Theory - Roots of a product :

 4.1    A product of several terms equals zero. 

 
When a product of two or more terms equals zero, then at least one of the terms must be zero. 

 
We shall now solve each term = 0 separately 

 
In other words, we are going to solve as many equations as there are terms in the product 

 
Any solution of term = 0 solves product = 0 as well.

Solving a Single Variable Equation :

 4.2      Solve  :    x2-3 = 0 

 
Add  3  to both sides of the equation : 
 
                     x2 = 3
 
 
When two things are equal, their square roots are equal. Taking the square root of the two sides of the equation we get:  
 
                     x  =  ± √ 3  

 
The equation has two real solutions  
 
These solutions are  x = ± √3 = ± 1.7321  
 

Solving a Single Variable Equation :

 4.3      Solve  :    4x2+1 = 0 

 
Subtract  1  from both sides of the equation : 
 
                     4x2 = -1
Divide both sides of the equation by 4:
                     x2 = -1/4 = -0.250
 
 
When two things are equal, their square roots are equal. Taking the square root of the two sides of the equation we get:  
 
                     x  =  ± √ -1/4  

 
In Math,  i  is called the imaginary unit. It satisfies   i2  =-1. Both   i   and   -i   are the square roots of   -1 

Accordingly,  √ -1/4  =
                    √ -1• 1/4   =
                    √ -1 •√  1/4   =
                    i •  √ 1/4

The equation has no real solutions. It has 2 imaginary, or complex solutions.

                      x=  0.0000 + 0.5000
                      x=  0.0000 - 0.5000

Supplement : Solving Quadratic Equation Directly

Solving    4x4-11x2-3  = 0   directly 

Earlier we factored this polynomial by splitting the middle term. let us now solve the equation by Completing The Square and by using the Quadratic Formula

Solving a Single Variable Equation :

Equations which are reducible to quadratic :

 5.1     Solve   4x4-11x2-3 = 0

This equation is reducible to quadratic. What this means is that using a new variable, we can rewrite this equation as a quadratic equation Using  w , such that  w = x2  transforms the equation into :
 4w2-11w-3 = 0

Solving this new equation using the quadratic formula we get two real solutions :
   3.0000  or  -0.2500

Now that we know the value(s) of  w , we can calculate  x  since  x  is  √ w  

Doing just this we discover that the solutions of
   4x4-11x2-3 = 0
  are either : 
  x =√ 3.000 = 1.73205  or :
  x =√ 3.000 = -1.73205  or :
  x =√-0.250 = 0.0 + 0.50000 i  or :
  x =√-0.250 = 0.0 - 0.50000 i

Four solutions were found :

  1.   x=  0.0000 - 0.5000
  2.   x=  0.0000 + 0.5000
  3.  x = ± √3 = ± 1.7321

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