Solution - Reducing fractions to their lowest terms
Other Ways to Solve
Reducing fractions to their lowest termsStep by Step Solution
Step 1 :
m
Simplify —
3
Equation at the end of step 1 :
m (5 - (— • m)) - 15 3Step 2 :
Rewriting the whole as an Equivalent Fraction :
2.1 Subtracting a fraction from a whole
Rewrite the whole as a fraction using 3 as the denominator :
5 5 • 3
5 = — = —————
1 3
Equivalent fraction : The fraction thus generated looks different but has the same value as the whole
Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator
Adding fractions that have a common denominator :
2.2 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
5 • 3 - (m2) 15 - m2
———————————— = ———————
3 3
Equation at the end of step 2 :
(15 - m2)
————————— - 15
3
Step 3 :
Rewriting the whole as an Equivalent Fraction :
3.1 Subtracting a whole from a fraction
Rewrite the whole as a fraction using 3 as the denominator :
15 15 • 3
15 = —— = ——————
1 3
Trying to factor as a Difference of Squares :
3.2 Factoring: 15 - m2
Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)
Proof : (A+B) • (A-B) =
A2 - AB + BA - B2 =
A2 - AB + AB - B2 =
A2 - B2
Note : AB = BA is the commutative property of multiplication.
Note : - AB + AB equals zero and is therefore eliminated from the expression.
Check : 15 is not a square !!
Ruling : Binomial can not be factored as the
difference of two perfect squares
Adding fractions that have a common denominator :
3.3 Adding up the two equivalent fractions
(15-m2) - (15 • 3) -m2 - 30
—————————————————— = ————————
3 3
Step 4 :
Pulling out like terms :
4.1 Pull out like factors :
-m2 - 30 = -1 • (m2 + 30)
Polynomial Roots Calculator :
4.2 Find roots (zeroes) of : F(m) = m2 + 30
Polynomial Roots Calculator is a set of methods aimed at finding values of m for which F(m)=0
Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers m which can be expressed as the quotient of two integers
The Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading Coefficient
In this case, the Leading Coefficient is 1 and the Trailing Constant is 30.
The factor(s) are:
of the Leading Coefficient : 1
of the Trailing Constant : 1 ,2 ,3 ,5 ,6 ,10 ,15 ,30
Let us test ....
| P | Q | P/Q | F(P/Q) | Divisor | |||||
|---|---|---|---|---|---|---|---|---|---|
| -1 | 1 | -1.00 | 31.00 | ||||||
| -2 | 1 | -2.00 | 34.00 | ||||||
| -3 | 1 | -3.00 | 39.00 | ||||||
| -5 | 1 | -5.00 | 55.00 | ||||||
| -6 | 1 | -6.00 | 66.00 | ||||||
| -10 | 1 | -10.00 | 130.00 | ||||||
| -15 | 1 | -15.00 | 255.00 | ||||||
| -30 | 1 | -30.00 | 930.00 | ||||||
| 1 | 1 | 1.00 | 31.00 | ||||||
| 2 | 1 | 2.00 | 34.00 | ||||||
| 3 | 1 | 3.00 | 39.00 | ||||||
| 5 | 1 | 5.00 | 55.00 | ||||||
| 6 | 1 | 6.00 | 66.00 | ||||||
| 10 | 1 | 10.00 | 130.00 | ||||||
| 15 | 1 | 15.00 | 255.00 | ||||||
| 30 | 1 | 30.00 | 930.00 |
Polynomial Roots Calculator found no rational roots
Final result :
+m2 + 30
————————
3
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