Solution - Reducing fractions to their lowest terms
Other Ways to Solve
Reducing fractions to their lowest termsStep by Step Solution
Step 1 :
30
Simplify ——
x
Equation at the end of step 1 :
30
(6x - ——) - 5
x
Step 2 :
Rewriting the whole as an Equivalent Fraction :
2.1 Subtracting a fraction from a whole
Rewrite the whole as a fraction using x as the denominator :
6x 6x • x
6x = —— = ——————
1 x
Equivalent fraction : The fraction thus generated looks different but has the same value as the whole
Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator
Adding fractions that have a common denominator :
2.2 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
6x • x - (30) 6x2 - 30
————————————— = ————————
x x
Equation at the end of step 2 :
(6x2 - 30)
—————————— - 5
x
Step 3 :
Rewriting the whole as an Equivalent Fraction :
3.1 Subtracting a whole from a fraction
Rewrite the whole as a fraction using x as the denominator :
5 5 • x
5 = — = —————
1 x
Step 4 :
Pulling out like terms :
4.1 Pull out like factors :
6x2 - 30 = 6 • (x2 - 5)
Trying to factor as a Difference of Squares :
4.2 Factoring: x2 - 5
Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)
Proof : (A+B) • (A-B) =
A2 - AB + BA - B2 =
A2 - AB + AB - B2 =
A2 - B2
Note : AB = BA is the commutative property of multiplication.
Note : - AB + AB equals zero and is therefore eliminated from the expression.
Check : 5 is not a square !!
Ruling : Binomial can not be factored as the difference of two perfect squares.
Adding fractions that have a common denominator :
4.3 Adding up the two equivalent fractions
6 • (x2-5) - (5 • x) 6x2 - 5x - 30
———————————————————— = —————————————
x x
Trying to factor by splitting the middle term
4.4 Factoring 6x2 - 5x - 30
The first term is, 6x2 its coefficient is 6 .
The middle term is, -5x its coefficient is -5 .
The last term, "the constant", is -30
Step-1 : Multiply the coefficient of the first term by the constant 6 • -30 = -180
Step-2 : Find two factors of -180 whose sum equals the coefficient of the middle term, which is -5 .
| -180 | + | 1 | = | -179 | ||
| -90 | + | 2 | = | -88 | ||
| -60 | + | 3 | = | -57 | ||
| -45 | + | 4 | = | -41 | ||
| -36 | + | 5 | = | -31 | ||
| -30 | + | 6 | = | -24 |
For tidiness, printing of 12 lines which failed to find two such factors, was suppressed
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Final result :
6x2 - 5x - 30
—————————————
x
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