Solution - Quadratic equations
Step by Step Solution
Step by step solution :
Step 1 :
Equation at the end of step 1 :
(32x2 - 155x) - 500 = 0
Step 2 :
Trying to factor by splitting the middle term
2.1 Factoring 9x2-155x-500
The first term is, 9x2 its coefficient is 9 .
The middle term is, -155x its coefficient is -155 .
The last term, "the constant", is -500
Step-1 : Multiply the coefficient of the first term by the constant 9 • -500 = -4500
Step-2 : Find two factors of -4500 whose sum equals the coefficient of the middle term, which is -155 .
-4500 | + | 1 | = | -4499 | ||
-2250 | + | 2 | = | -2248 | ||
-1500 | + | 3 | = | -1497 | ||
-1125 | + | 4 | = | -1121 | ||
-900 | + | 5 | = | -895 | ||
-750 | + | 6 | = | -744 | ||
-500 | + | 9 | = | -491 | ||
-450 | + | 10 | = | -440 | ||
-375 | + | 12 | = | -363 | ||
-300 | + | 15 | = | -285 | ||
-250 | + | 18 | = | -232 | ||
-225 | + | 20 | = | -205 | ||
-180 | + | 25 | = | -155 | That's it |
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -180 and 25
9x2 - 180x + 25x - 500
Step-4 : Add up the first 2 terms, pulling out like factors :
9x • (x-20)
Add up the last 2 terms, pulling out common factors :
25 • (x-20)
Step-5 : Add up the four terms of step 4 :
(9x+25) • (x-20)
Which is the desired factorization
Equation at the end of step 2 :
(x - 20) • (9x + 25) = 0
Step 3 :
Theory - Roots of a product :
3.1 A product of several terms equals zero.
When a product of two or more terms equals zero, then at least one of the terms must be zero.
We shall now solve each term = 0 separately
In other words, we are going to solve as many equations as there are terms in the product
Any solution of term = 0 solves product = 0 as well.
Solving a Single Variable Equation :
3.2 Solve : x-20 = 0
Add 20 to both sides of the equation :
x = 20
Solving a Single Variable Equation :
3.3 Solve : 9x+25 = 0
Subtract 25 from both sides of the equation :
9x = -25
Divide both sides of the equation by 9:
x = -25/9 = -2.778
Supplement : Solving Quadratic Equation Directly
Solving 9x2-155x-500 = 0 directly
Earlier we factored this polynomial by splitting the middle term. let us now solve the equation by Completing The Square and by using the Quadratic Formula
Parabola, Finding the Vertex :
4.1 Find the Vertex of y = 9x2-155x-500
Parabolas have a highest or a lowest point called the Vertex . Our parabola opens up and accordingly has a lowest point (AKA absolute minimum) . We know this even before plotting "y" because the coefficient of the first term, 9 , is positive (greater than zero).
Each parabola has a vertical line of symmetry that passes through its vertex. Because of this symmetry, the line of symmetry would, for example, pass through the midpoint of the two x -intercepts (roots or solutions) of the parabola. That is, if the parabola has indeed two real solutions.
Parabolas can model many real life situations, such as the height above ground, of an object thrown upward, after some period of time. The vertex of the parabola can provide us with information, such as the maximum height that object, thrown upwards, can reach. For this reason we want to be able to find the coordinates of the vertex.
For any parabola,Ax2+Bx+C,the x -coordinate of the vertex is given by -B/(2A) . In our case the x coordinate is 8.6111
Plugging into the parabola formula 8.6111 for x we can calculate the y -coordinate :
y = 9.0 * 8.61 * 8.61 - 155.0 * 8.61 - 500.0
or y = -1167.361
Parabola, Graphing Vertex and X-Intercepts :
Root plot for : y = 9x2-155x-500
Axis of Symmetry (dashed) {x}={ 8.61}
Vertex at {x,y} = { 8.61,-1167.36}
x -Intercepts (Roots) :
Root 1 at {x,y} = {-2.78, 0.00}
Root 2 at {x,y} = {20.00, 0.00}
Solve Quadratic Equation by Completing The Square
4.2 Solving 9x2-155x-500 = 0 by Completing The Square .
Divide both sides of the equation by 9 to have 1 as the coefficient of the first term :
x2-(155/9)x-(500/9) = 0
Add 500/9 to both side of the equation :
x2-(155/9)x = 500/9
Now the clever bit: Take the coefficient of x , which is 155/9 , divide by two, giving 155/18 , and finally square it giving 24025/324
Add 24025/324 to both sides of the equation :
On the right hand side we have :
500/9 + 24025/324 The common denominator of the two fractions is 324 Adding (18000/324)+(24025/324) gives 42025/324
So adding to both sides we finally get :
x2-(155/9)x+(24025/324) = 42025/324
Adding 24025/324 has completed the left hand side into a perfect square :
x2-(155/9)x+(24025/324) =
(x-(155/18)) • (x-(155/18)) =
(x-(155/18))2
Things which are equal to the same thing are also equal to one another. Since
x2-(155/9)x+(24025/324) = 42025/324 and
x2-(155/9)x+(24025/324) = (x-(155/18))2
then, according to the law of transitivity,
(x-(155/18))2 = 42025/324
We'll refer to this Equation as Eq. #4.2.1
The Square Root Principle says that When two things are equal, their square roots are equal.
Note that the square root of
(x-(155/18))2 is
(x-(155/18))2/2 =
(x-(155/18))1 =
x-(155/18)
Now, applying the Square Root Principle to Eq. #4.2.1 we get:
x-(155/18) = √ 42025/324
Add 155/18 to both sides to obtain:
x = 155/18 + √ 42025/324
Since a square root has two values, one positive and the other negative
x2 - (155/9)x - (500/9) = 0
has two solutions:
x = 155/18 + √ 42025/324
or
x = 155/18 - √ 42025/324
Note that √ 42025/324 can be written as
√ 42025 / √ 324 which is 205 / 18
Solve Quadratic Equation using the Quadratic Formula
4.3 Solving 9x2-155x-500 = 0 by the Quadratic Formula .
According to the Quadratic Formula, x , the solution for Ax2+Bx+C = 0 , where A, B and C are numbers, often called coefficients, is given by :
- B ± √ B2-4AC
x = ————————
2A
In our case, A = 9
B = -155
C = -500
Accordingly, B2 - 4AC =
24025 - (-18000) =
42025
Applying the quadratic formula :
155 ± √ 42025
x = ————————
18
Can √ 42025 be simplified ?
Yes! The prime factorization of 42025 is
5•5•41•41
To be able to remove something from under the radical, there have to be 2 instances of it (because we are taking a square i.e. second root).
√ 42025 = √ 5•5•41•41 =5•41•√ 1 =
± 205 • √ 1 =
± 205
So now we are looking at:
x = ( 155 ± 205) / 18
Two real solutions:
x =(155+√42025)/18=(155+205)/18= 20.000
or:
x =(155-√42025)/18=(155-205)/18= -2.778
Two solutions were found :
- x = -25/9 = -2.778
- x = 20
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