Solution - Adding, subtracting and finding the least common multiple
Other Ways to Solve
Adding, subtracting and finding the least common multipleStep by Step Solution
Reformatting the input :
Changes made to your input should not affect the solution:
(1): "b2" was replaced by "b^2". 1 more similar replacement(s).
Step 1 :
a
Simplify —
3
Equation at the end of step 1 :
b a ((((a•—)•(a2))-(b2))+(—•a))+b 9 3Step 2 :
b Simplify — 9
Equation at the end of step 2 :
b a2
((((a • —) • a2) - b2) + ——) + b
9 3
Step 3 :
Multiplying exponential expressions :
3.1 a1 multiplied by a2 = a(1 + 2) = a3
Equation at the end of step 3 :
a3b a2
((——— - b2) + ——) + b
9 3
Step 4 :
Rewriting the whole as an Equivalent Fraction :
4.1 Subtracting a whole from a fraction
Rewrite the whole as a fraction using 9 as the denominator :
b2 b2 • 9
b2 = —— = ——————
1 9
Equivalent fraction : The fraction thus generated looks different but has the same value as the whole
Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator
Adding fractions that have a common denominator :
4.2 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
a3b - (b2 • 9) a3b - 9b2
—————————————— = —————————
9 9
Equation at the end of step 4 :
(a3b - 9b2) a2
(——————————— + ——) + b
9 3
Step 5 :
Step 6 :
Pulling out like terms :
6.1 Pull out like factors :
a3b - 9b2 = b • (a3 - 9b)
Trying to factor as a Difference of Cubes:
6.2 Factoring: a3 - 9b
Theory : A difference of two perfect cubes, a3 - b3 can be factored into
(a-b) • (a2 +ab +b2)
Proof : (a-b)•(a2+ab+b2) =
a3+a2b+ab2-ba2-b2a-b3 =
a3+(a2b-ba2)+(ab2-b2a)-b3 =
a3+0+0-b3 =
a3-b3
Check : 9 is not a cube !!
Ruling : Binomial can not be factored as the difference of two perfect cubes
Calculating the Least Common Multiple :
6.3 Find the Least Common Multiple
The left denominator is : 9
The right denominator is : 3
Prime Factor | Left Denominator | Right Denominator | L.C.M = Max {Left,Right} |
---|---|---|---|
3 | 2 | 1 | 2 |
Product of all Prime Factors | 9 | 3 | 9 |
Least Common Multiple:
9
Calculating Multipliers :
6.4 Calculate multipliers for the two fractions
Denote the Least Common Multiple by L.C.M
Denote the Left Multiplier by Left_M
Denote the Right Multiplier by Right_M
Denote the Left Deniminator by L_Deno
Denote the Right Multiplier by R_Deno
Left_M = L.C.M / L_Deno = 1
Right_M = L.C.M / R_Deno = 3
Making Equivalent Fractions :
6.5 Rewrite the two fractions into equivalent fractions
Two fractions are called equivalent if they have the same numeric value.
For example : 1/2 and 2/4 are equivalent, y/(y+1)2 and (y2+y)/(y+1)3 are equivalent as well.
To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.
L. Mult. • L. Num. b • (a3-9b) —————————————————— = ——————————— L.C.M 9 R. Mult. • R. Num. a2 • 3 —————————————————— = —————— L.C.M 9
Adding fractions that have a common denominator :
6.6 Adding up the two equivalent fractions
b • (a3-9b) + a2 • 3 a3b + 3a2 - 9b2
———————————————————— = ———————————————
9 9
Equation at the end of step 6 :
(a3b + 3a2 - 9b2)
————————————————— + b
9
Step 7 :
Rewriting the whole as an Equivalent Fraction :
7.1 Adding a whole to a fraction
Rewrite the whole as a fraction using 9 as the denominator :
b b • 9
b = — = —————
1 9
Trying to factor a multi variable polynomial :
7.2 Factoring a3b + 3a2 - 9b2
Try to factor this multi-variable trinomial using trial and error
Factorization fails
Adding fractions that have a common denominator :
7.3 Adding up the two equivalent fractions
(a3b+3a2-9b2) + b • 9 a3b + 3a2 - 9b2 + 9b
————————————————————— = ————————————————————
9 9
Checking for a perfect cube :
7.4 a3b + 3a2 + 9b2 + 9b is not a perfect cube
Final result :
a3b + 3a2 + 9b2 + 9b
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