Solution - Factoring binomials using the difference of squares
Step by Step Solution
Reformatting the input :
Changes made to your input should not affect the solution:
(1): "k4" was replaced by "k^4".
Step by step solution :
Step 1 :
Equation at the end of step 1 :
(k2) - 22k4 = 0Step 2 :
Step 3 :
Pulling out like terms :
3.1 Pull out like factors :
k2 - 4k4 = -k2 • (4k2 - 1)
Trying to factor as a Difference of Squares :
3.2 Factoring: 4k2 - 1
Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)
Proof : (A+B) • (A-B) =
A2 - AB + BA - B2 =
A2 - AB + AB - B2 =
A2 - B2
Note : AB = BA is the commutative property of multiplication.
Note : - AB + AB equals zero and is therefore eliminated from the expression.
Check : 4 is the square of 2
Check : 1 is the square of 1
Check : k2 is the square of k1
Factorization is : (2k + 1) • (2k - 1)
Equation at the end of step 3 :
-k2 • (2k + 1) • (2k - 1) = 0
Step 4 :
Theory - Roots of a product :
4.1 A product of several terms equals zero.
When a product of two or more terms equals zero, then at least one of the terms must be zero.
We shall now solve each term = 0 separately
In other words, we are going to solve as many equations as there are terms in the product
Any solution of term = 0 solves product = 0 as well.
Solving a Single Variable Equation :
4.2 Solve : -k2 = 0
Multiply both sides of the equation by (-1) : k2 = 0
When two things are equal, their square roots are equal. Taking the square root of the two sides of the equation we get:
k = ± √ 0
Any root of zero is zero. This equation has one solution which is k = 0
Solving a Single Variable Equation :
4.3 Solve : 2k+1 = 0
Subtract 1 from both sides of the equation :
2k = -1
Divide both sides of the equation by 2:
k = -1/2 = -0.500
Solving a Single Variable Equation :
4.4 Solve : 2k-1 = 0
Add 1 to both sides of the equation :
2k = 1
Divide both sides of the equation by 2:
k = 1/2 = 0.500
Three solutions were found :
- k = 1/2 = 0.500
- k = -1/2 = -0.500
- k = 0
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