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Solution - Factoring multivariable polynomials

(t5s)(t2+5ts+25s2)
(t-5s)*(t^2+5ts+25s^2)

Step by Step Solution

Reformatting the input :

Changes made to your input should not affect the solution:

 (1): "s3"   was replaced by   "s^3".  1 more similar replacement(s).

Step  1  :

Equation at the end of step  1  :

  (t3) -  53s3

Step  2  :

Trying to factor as a Difference of Cubes:

 2.1      Factoring:  t3-125s3 

Theory : A difference of two perfect cubes,  a3 - b3 can be factored into
              (a-b) • (a2 +ab +b2)

Proof :  (a-b)•(a2+ab+b2) =
            a3+a2b+ab2-ba2-b2a-b3 =
            a3+(a2b-ba2)+(ab2-b2a)-b3 =
            a3+0+0-b3 =
            a3-b3


Check :  125  is the cube of   5 
Check :  t3 is the cube of   t1

Check :  s3 is the cube of   s1

Factorization is :
             (t - 5s)  •  (t2 + 5ts + 25s2) 

Trying to factor a multi variable polynomial :

 2.2    Factoring    t2 + 5ts + 25s2 

Try to factor this multi-variable trinomial using trial and error 

 
Factorization fails

Final result :

  (t - 5s) • (t2 + 5ts + 25s2)

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