Solution - Simplification or other simple results
w^4*(w^2+7w+14)
Other Ways to Solve
Simplification or other simple resultsStep by Step Solution
Step 1 :
Equation at the end of step 1 :
((w6) + (7 • (w5))) + (2•7w4)Step 2 :
Equation at the end of step 2 :
((w6) + 7w5) + (2•7w4)
Step 3 :
Step 4 :
Pulling out like terms :
4.1 Pull out like factors :
w6 + 7w5 + 14w4 = w4 • (w2 + 7w + 14)
Trying to factor by splitting the middle term
4.2 Factoring w2 + 7w + 14
The first term is, w2 its coefficient is 1 .
The middle term is, +7w its coefficient is 7 .
The last term, "the constant", is +14
Step-1 : Multiply the coefficient of the first term by the constant 1 • 14 = 14
Step-2 : Find two factors of 14 whose sum equals the coefficient of the middle term, which is 7 .
-14 | + | -1 | = | -15 | ||
-7 | + | -2 | = | -9 | ||
-2 | + | -7 | = | -9 | ||
-1 | + | -14 | = | -15 | ||
1 | + | 14 | = | 15 | ||
2 | + | 7 | = | 9 | ||
7 | + | 2 | = | 9 | ||
14 | + | 1 | = | 15 |
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Final result :
w4 • (w2 + 7w + 14)
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