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Solution - Simplification or other simple results

w4(w2+7w+14)
w^4*(w^2+7w+14)

Step by Step Solution

Step  1  :

Equation at the end of step  1  :

  ((w6) +  (7 • (w5))) +  (2•7w4)

Step  2  :

Equation at the end of step  2  :

  ((w6) +  7w5) +  (2•7w4)

Step  3  :

Step  4  :

Pulling out like terms :

 4.1     Pull out like factors :

   w6 + 7w5 + 14w4  =   w4 • (w2 + 7w + 14) 

Trying to factor by splitting the middle term

 4.2     Factoring  w2 + 7w + 14 

The first term is,  w2  its coefficient is  1 .
The middle term is,  +7w  its coefficient is  7 .
The last term, "the constant", is  +14 

Step-1 : Multiply the coefficient of the first term by the constant   1 • 14 = 14 

Step-2 : Find two factors of  14  whose sum equals the coefficient of the middle term, which is   7 .

     -14   +   -1   =   -15
     -7   +   -2   =   -9
     -2   +   -7   =   -9
     -1   +   -14   =   -15
     1   +   14   =   15
     2   +   7   =   9
     7   +   2   =   9
     14   +   1   =   15


Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored

Final result :

  w4 • (w2 + 7w + 14)

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