Solution - Adding, subtracting and finding the least common multiple
Step by Step Solution
Rearrange:
Rearrange the equation by subtracting what is to the right of the less equal sign from both sides of the inequality :
x/2+13/10-(x/5+1)≤0
Step by step solution :
Step 1 :
x
Simplify —
5
Equation at the end of step 1 :
x 13 x
(— + ——) - (— + 1) ≤ 0
2 10 5
Step 2 :
Rewriting the whole as an Equivalent Fraction :
2.1 Adding a whole to a fraction
Rewrite the whole as a fraction using 5 as the denominator :
1 1 • 5
1 = — = —————
1 5
Equivalent fraction : The fraction thus generated looks different but has the same value as the whole
Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator
Adding fractions that have a common denominator :
2.2 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
x + 5 x + 5
————— = —————
5 5
Equation at the end of step 2 :
x 13 (x + 5)
(— + ——) - ——————— ≤ 0
2 10 5
Step 3 :
13
Simplify ——
10
Equation at the end of step 3 :
x 13 (x + 5)
(— + ——) - ——————— ≤ 0
2 10 5
Step 4 :
x
Simplify —
2
Equation at the end of step 4 :
x 13 (x + 5)
(— + ——) - ——————— ≤ 0
2 10 5
Step 5 :
Calculating the Least Common Multiple :
5.1 Find the Least Common Multiple
The left denominator is : 2
The right denominator is : 10
Prime Factor | Left Denominator | Right Denominator | L.C.M = Max {Left,Right} |
---|---|---|---|
2 | 1 | 1 | 1 |
5 | 0 | 1 | 1 |
Product of all Prime Factors | 2 | 10 | 10 |
Least Common Multiple:
10
Calculating Multipliers :
5.2 Calculate multipliers for the two fractions
Denote the Least Common Multiple by L.C.M
Denote the Left Multiplier by Left_M
Denote the Right Multiplier by Right_M
Denote the Left Deniminator by L_Deno
Denote the Right Multiplier by R_Deno
Left_M = L.C.M / L_Deno = 5
Right_M = L.C.M / R_Deno = 1
Making Equivalent Fractions :
5.3 Rewrite the two fractions into equivalent fractions
Two fractions are called equivalent if they have the same numeric value.
For example : 1/2 and 2/4 are equivalent, y/(y+1)2 and (y2+y)/(y+1)3 are equivalent as well.
To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.
L. Mult. • L. Num. x • 5 —————————————————— = ————— L.C.M 10 R. Mult. • R. Num. 13 —————————————————— = —— L.C.M 10
Adding fractions that have a common denominator :
5.4 Adding up the two equivalent fractions
x • 5 + 13 5x + 13
—————————— = ———————
10 10
Equation at the end of step 5 :
(5x + 13) (x + 5)
————————— - ——————— ≤ 0
10 5
Step 6 :
Calculating the Least Common Multiple :
6.1 Find the Least Common Multiple
The left denominator is : 10
The right denominator is : 5
Prime Factor | Left Denominator | Right Denominator | L.C.M = Max {Left,Right} |
---|---|---|---|
2 | 1 | 0 | 1 |
5 | 1 | 1 | 1 |
Product of all Prime Factors | 10 | 5 | 10 |
Least Common Multiple:
10
Calculating Multipliers :
6.2 Calculate multipliers for the two fractions
Denote the Least Common Multiple by L.C.M
Denote the Left Multiplier by Left_M
Denote the Right Multiplier by Right_M
Denote the Left Deniminator by L_Deno
Denote the Right Multiplier by R_Deno
Left_M = L.C.M / L_Deno = 1
Right_M = L.C.M / R_Deno = 2
Making Equivalent Fractions :
6.3 Rewrite the two fractions into equivalent fractions
L. Mult. • L. Num. (5x+13) —————————————————— = ——————— L.C.M 10 R. Mult. • R. Num. (x+5) • 2 —————————————————— = ————————— L.C.M 10
Adding fractions that have a common denominator :
6.4 Adding up the two equivalent fractions
(5x+13) - ((x+5) • 2) 3x + 3
————————————————————— = ——————
10 10
Step 7 :
Pulling out like terms :
7.1 Pull out like factors :
3x + 3 = 3 • (x + 1)
Equation at the end of step 7 :
3 • (x + 1)
——————————— ≤ 0
10
Step 8 :
8.1 Multiply both sides by 10
8.2 Divide both sides by 3
Solve Basic Inequality :
8.3 Subtract 1 from both sides
x ≤ -1
Inequality Plot :
8.4 Inequality plot for
0.300 X + 0.300 ≤ 0
One solution was found :
x ≤ -1How did we do?
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