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Solution - Factoring multivariable polynomials

(x2+y2)(x22y2)
(x^2+y^2)*(x^2-2y^2)

Step by Step Solution

Reformatting the input :

Changes made to your input should not affect the solution:

 (1): "y4"   was replaced by   "y^4".  3 more similar replacement(s).

Step  1  :

Equation at the end of step  1  :

  ((x4)-((x2)•(y2)))-2y4

Step  2  :

Trying to factor a multi variable polynomial :

 2.1    Factoring    x4 - x2y2 - 2y4 

Try to factor this multi-variable trinomial using trial and error 

 
Found a factorization  :  (x2 + y2)•(x2 - 2y2)

Trying to factor as a Difference of Squares :

 2.2      Factoring:  x2-2y2 

Theory : A difference of two perfect squares,  A2 - B2  can be factored into  (A+B) • (A-B)

Proof :  (A+B) • (A-B) =
         A2 - AB + BA - B2 =
         A2 - AB + AB - B2 =
         A2 - B2

Note :  AB = BA is the commutative property of multiplication.

Note :  - AB + AB equals zero and is therefore eliminated from the expression.

Check : 2 is not a square !!

Ruling : Binomial can not be factored as the difference of two perfect squares.

Final result :

  (x2 + y2) • (x2 - 2y2)

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