Solution - Factoring multivariable polynomials
(x-c)*(x^2+xc+c^2)
Other Ways to Solve
Factoring multivariable polynomialsStep by Step Solution
Step 1 :
Trying to factor as a Difference of Cubes:
1.1 Factoring: x3-c3
Theory : A difference of two perfect cubes, a3 - b3 can be factored into
(a-b) • (a2 +ab +b2)
Proof : (a-b)•(a2+ab+b2) =
a3+a2b+ab2-ba2-b2a-b3 =
a3+(a2b-ba2)+(ab2-b2a)-b3 =
a3+0+0-b3 =
a3-b3
Check : x3 is the cube of x1
Check : c3 is the cube of c1
Factorization is :
(x - c) • (x2 + xc + c2)
Trying to factor a multi variable polynomial :
1.2 Factoring x2 + xc + c2
Try to factor this multi-variable trinomial using trial and error
Factorization fails
Final result :
(x - c) • (x2 + xc + c2)
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