Solution - Finding the roots of polynomials
Other Ways to Solve
Finding the roots of polynomialsStep by Step Solution
Step by step solution :
Step 1 :
Equation at the end of step 1 :
((((x4)+(5•(x3)))-24x2)+40x)-192 = 0Step 2 :
Equation at the end of step 2 :
((((x4) + 5x3) - 24x2) + 40x) - 192 = 0
Step 3 :
Polynomial Roots Calculator :
3.1 Find roots (zeroes) of : F(x) = x4+5x3-16x2+40x-192
Polynomial Roots Calculator is a set of methods aimed at finding values of x for which F(x)=0
Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers x which can be expressed as the quotient of two integers
The Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading Coefficient
In this case, the Leading Coefficient is 1 and the Trailing Constant is -192.
The factor(s) are:
of the Leading Coefficient : 1
of the Trailing Constant : 1 ,2 ,3 ,4 ,6 ,8 ,12 ,16 ,24 ,32 , etc
Let us test ....
| P | Q | P/Q | F(P/Q) | Divisor | |||||
|---|---|---|---|---|---|---|---|---|---|
| -1 | 1 | -1.00 | -252.00 | ||||||
| -2 | 1 | -2.00 | -360.00 | ||||||
| -3 | 1 | -3.00 | -510.00 | ||||||
| -4 | 1 | -4.00 | -672.00 | ||||||
| -6 | 1 | -6.00 | -792.00 | ||||||
| -8 | 1 | -8.00 | 0.00 | x+8 | |||||
| -12 | 1 | -12.00 | 9120.00 | ||||||
| -16 | 1 | -16.00 | 40128.00 | ||||||
| -24 | 1 | -24.00 | 252288.00 | ||||||
| -32 | 1 | -32.00 | 866880.00 | ||||||
| 1 | 1 | 1.00 | -162.00 | ||||||
| 2 | 1 | 2.00 | -120.00 | ||||||
| 3 | 1 | 3.00 | 0.00 | x-3 | |||||
| 4 | 1 | 4.00 | 288.00 | ||||||
| 6 | 1 | 6.00 | 1848.00 | ||||||
| 8 | 1 | 8.00 | 5760.00 | ||||||
| 12 | 1 | 12.00 | 27360.00 | ||||||
| 16 | 1 | 16.00 | 82368.00 | ||||||
| 24 | 1 | 24.00 | 392448.00 | ||||||
| 32 | 1 | 32.00 | 1197120.00 |
The Factor Theorem states that if P/Q is root of a polynomial then this polynomial can be divided by q*x-p Note that q and p originate from P/Q reduced to its lowest terms
In our case this means that
x4+5x3-16x2+40x-192
can be divided by 2 different polynomials,including by x-3
Polynomial Long Division :
3.2 Polynomial Long Division
Dividing : x4+5x3-16x2+40x-192
("Dividend")
By : x-3 ("Divisor")
| dividend | x4 | + | 5x3 | - | 16x2 | + | 40x | - | 192 | ||
| - divisor | * x3 | x4 | - | 3x3 | |||||||
| remainder | 8x3 | - | 16x2 | + | 40x | - | 192 | ||||
| - divisor | * 8x2 | 8x3 | - | 24x2 | |||||||
| remainder | 8x2 | + | 40x | - | 192 | ||||||
| - divisor | * 8x1 | 8x2 | - | 24x | |||||||
| remainder | 64x | - | 192 | ||||||||
| - divisor | * 64x0 | 64x | - | 192 | |||||||
| remainder | 0 |
Quotient : x3+8x2+8x+64 Remainder: 0
Polynomial Roots Calculator :
3.3 Find roots (zeroes) of : F(x) = x3+8x2+8x+64
See theory in step 3.1
In this case, the Leading Coefficient is 1 and the Trailing Constant is 64.
The factor(s) are:
of the Leading Coefficient : 1
of the Trailing Constant : 1 ,2 ,4 ,8 ,16 ,32 ,64
Let us test ....
| P | Q | P/Q | F(P/Q) | Divisor | |||||
|---|---|---|---|---|---|---|---|---|---|
| -1 | 1 | -1.00 | 63.00 | ||||||
| -2 | 1 | -2.00 | 72.00 | ||||||
| -4 | 1 | -4.00 | 96.00 | ||||||
| -8 | 1 | -8.00 | 0.00 | x+8 | |||||
| -16 | 1 | -16.00 | -2112.00 | ||||||
| -32 | 1 | -32.00 | -24768.00 | ||||||
| -64 | 1 | -64.00 | -229824.00 | ||||||
| 1 | 1 | 1.00 | 81.00 | ||||||
| 2 | 1 | 2.00 | 120.00 | ||||||
| 4 | 1 | 4.00 | 288.00 | ||||||
| 8 | 1 | 8.00 | 1152.00 | ||||||
| 16 | 1 | 16.00 | 6336.00 | ||||||
| 32 | 1 | 32.00 | 41280.00 | ||||||
| 64 | 1 | 64.00 | 295488.00 |
The Factor Theorem states that if P/Q is root of a polynomial then this polynomial can be divided by q*x-p Note that q and p originate from P/Q reduced to its lowest terms
In our case this means that
x3+8x2+8x+64
can be divided with x+8
Polynomial Long Division :
3.4 Polynomial Long Division
Dividing : x3+8x2+8x+64
("Dividend")
By : x+8 ("Divisor")
| dividend | x3 | + | 8x2 | + | 8x | + | 64 | ||
| - divisor | * x2 | x3 | + | 8x2 | |||||
| remainder | 8x | + | 64 | ||||||
| - divisor | * 0x1 | ||||||||
| remainder | 8x | + | 64 | ||||||
| - divisor | * 8x0 | 8x | + | 64 | |||||
| remainder | 0 |
Quotient : x2+8 Remainder: 0
Polynomial Roots Calculator :
3.5 Find roots (zeroes) of : F(x) = x2+8
See theory in step 3.1
In this case, the Leading Coefficient is 1 and the Trailing Constant is 8.
The factor(s) are:
of the Leading Coefficient : 1
of the Trailing Constant : 1 ,2 ,4 ,8
Let us test ....
| P | Q | P/Q | F(P/Q) | Divisor | |||||
|---|---|---|---|---|---|---|---|---|---|
| -1 | 1 | -1.00 | 9.00 | ||||||
| -2 | 1 | -2.00 | 12.00 | ||||||
| -4 | 1 | -4.00 | 24.00 | ||||||
| -8 | 1 | -8.00 | 72.00 | ||||||
| 1 | 1 | 1.00 | 9.00 | ||||||
| 2 | 1 | 2.00 | 12.00 | ||||||
| 4 | 1 | 4.00 | 24.00 | ||||||
| 8 | 1 | 8.00 | 72.00 |
Polynomial Roots Calculator found no rational roots
Equation at the end of step 3 :
(x2 + 8) • (x + 8) • (x - 3) = 0
Step 4 :
Theory - Roots of a product :
4.1 A product of several terms equals zero.
When a product of two or more terms equals zero, then at least one of the terms must be zero.
We shall now solve each term = 0 separately
In other words, we are going to solve as many equations as there are terms in the product
Any solution of term = 0 solves product = 0 as well.
Solving a Single Variable Equation :
4.2 Solve : x2+8 = 0
Subtract 8 from both sides of the equation :
x2 = -8
When two things are equal, their square roots are equal. Taking the square root of the two sides of the equation we get:
x = ± √ -8
In Math, i is called the imaginary unit. It satisfies i2 =-1. Both i and -i are the square roots of -1
Accordingly, √ -8 =
√ -1• 8 =
√ -1 •√ 8 =
i • √ 8
Can √ 8 be simplified ?
Yes! The prime factorization of 8 is
2•2•2
To be able to remove something from under the radical, there have to be 2 instances of it (because we are taking a square i.e. second root).
√ 8 = √ 2•2•2 =
± 2 • √ 2
The equation has no real solutions. It has 2 imaginary, or complex solutions.
x= 0.0000 + 2.8284 i
x= 0.0000 - 2.8284 i
Solving a Single Variable Equation :
4.3 Solve : x+8 = 0
Subtract 8 from both sides of the equation :
x = -8
Solving a Single Variable Equation :
4.4 Solve : x-3 = 0
Add 3 to both sides of the equation :
x = 3
Four solutions were found :
- x = 3
- x = -8
- x= 0.0000 - 2.8284 i
- x= 0.0000 + 2.8284 i
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