Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: v=-67,6
v=-\frac{6}{7} , 6
Decimal form: v=0.857,6
v=-0.857 , 6

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3v6|=|4v|
without the absolute value bars:

|x|=|y||3v6|=|4v|
x=+y(3v6)=(4v)
x=y(3v6)=(4v)
+x=y(3v6)=(4v)
x=y(3v6)=(4v)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3v6|=|4v|
x=+y , +x=y(3v6)=(4v)
x=y , x=y(3v6)=(4v)

2. Solve the two equations for v

10 additional steps

(-3v-6)=4v

Subtract from both sides:

(-3v-6)-4v=(4v)-4v

Group like terms:

(-3v-4v)-6=(4v)-4v

Simplify the arithmetic:

-7v-6=(4v)-4v

Simplify the arithmetic:

7v6=0

Add to both sides:

(-7v-6)+6=0+6

Simplify the arithmetic:

7v=0+6

Simplify the arithmetic:

7v=6

Divide both sides by :

(-7v)-7=6-7

Cancel out the negatives:

7v7=6-7

Simplify the fraction:

v=6-7

Move the negative sign from the denominator to the numerator:

v=-67

5 additional steps

(-3v-6)=-4v

Add to both sides:

(-3v-6)+6=(-4v)+6

Simplify the arithmetic:

-3v=(-4v)+6

Add to both sides:

(-3v)+4v=((-4v)+6)+4v

Simplify the arithmetic:

v=((-4v)+6)+4v

Group like terms:

v=(-4v+4v)+6

Simplify the arithmetic:

v=6

3. List the solutions

v=-67,6
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3v6|
y=|4v|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.