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Solution - Absolute value equations

Exact form: x=17,-13
x=\frac{1}{7} , -\frac{1}{3}
Decimal form: x=0.143,0.333
x=0.143 , -0.333

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x+1|=|5x|
without the absolute value bars:

|x|=|y||2x+1|=|5x|
x=+y(2x+1)=(5x)
x=y(2x+1)=(5x)
+x=y(2x+1)=(5x)
x=y(2x+1)=(5x)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x+1|=|5x|
x=+y , +x=y(2x+1)=(5x)
x=y , x=y(2x+1)=(5x)

2. Solve the two equations for x

10 additional steps

(-2x+1)=5x

Subtract from both sides:

(-2x+1)-5x=(5x)-5x

Group like terms:

(-2x-5x)+1=(5x)-5x

Simplify the arithmetic:

-7x+1=(5x)-5x

Simplify the arithmetic:

7x+1=0

Subtract from both sides:

(-7x+1)-1=0-1

Simplify the arithmetic:

7x=01

Simplify the arithmetic:

7x=1

Divide both sides by :

(-7x)-7=-1-7

Cancel out the negatives:

7x7=-1-7

Simplify the fraction:

x=-1-7

Cancel out the negatives:

x=17

7 additional steps

(-2x+1)=-5x

Subtract from both sides:

(-2x+1)-1=(-5x)-1

Simplify the arithmetic:

-2x=(-5x)-1

Add to both sides:

(-2x)+5x=((-5x)-1)+5x

Simplify the arithmetic:

3x=((-5x)-1)+5x

Group like terms:

3x=(-5x+5x)-1

Simplify the arithmetic:

3x=1

Divide both sides by :

(3x)3=-13

Simplify the fraction:

x=-13

3. List the solutions

x=17,-13
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x+1|
y=|5x|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.