Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: x=12625,-12595
x=\frac{12}{625} , -\frac{12}{595}
Decimal form: x=0.019,0.020
x=0.019 , -0.020

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|15x+12|=|610x|
without the absolute value bars:

|x|=|y||15x+12|=|610x|
x=+y(15x+12)=(610x)
x=y(15x+12)=(610x)
+x=y(15x+12)=(610x)
x=y(15x+12)=(610x)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||15x+12|=|610x|
x=+y , +x=y(15x+12)=(610x)
x=y , x=y(15x+12)=(610x)

2. Solve the two equations for x

10 additional steps

(-15x+12)=610x

Subtract from both sides:

(-15x+12)-610x=(610x)-610x

Group like terms:

(-15x-610x)+12=(610x)-610x

Simplify the arithmetic:

-625x+12=(610x)-610x

Simplify the arithmetic:

625x+12=0

Subtract from both sides:

(-625x+12)-12=0-12

Simplify the arithmetic:

625x=012

Simplify the arithmetic:

625x=12

Divide both sides by :

(-625x)-625=-12-625

Cancel out the negatives:

625x625=-12-625

Simplify the fraction:

x=-12-625

Cancel out the negatives:

x=12625

7 additional steps

(-15x+12)=-610x

Subtract from both sides:

(-15x+12)-12=(-610x)-12

Simplify the arithmetic:

-15x=(-610x)-12

Add to both sides:

(-15x)+610x=((-610x)-12)+610x

Simplify the arithmetic:

595x=((-610x)-12)+610x

Group like terms:

595x=(-610x+610x)-12

Simplify the arithmetic:

595x=12

Divide both sides by :

(595x)595=-12595

Simplify the fraction:

x=-12595

3. List the solutions

x=12625,-12595
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|15x+12|
y=|610x|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.