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Solution - Absolute value equations

Exact form: x=113,19
x=\frac{11}{3} , 19
Mixed number form: x=323,19
x=3\frac{2}{3} , 19
Decimal form: x=3.667,19
x=3.667 , 19

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x+15|=|x+4|
without the absolute value bars:

|x|=|y||2x+15|=|x+4|
x=+y(2x+15)=(x+4)
x=y(2x+15)=(x+4)
+x=y(2x+15)=(x+4)
x=y(2x+15)=(x+4)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x+15|=|x+4|
x=+y , +x=y(2x+15)=(x+4)
x=y , x=y(2x+15)=(x+4)

2. Solve the two equations for x

11 additional steps

(-2x+15)=(x+4)

Subtract from both sides:

(-2x+15)-x=(x+4)-x

Group like terms:

(-2x-x)+15=(x+4)-x

Simplify the arithmetic:

-3x+15=(x+4)-x

Group like terms:

-3x+15=(x-x)+4

Simplify the arithmetic:

3x+15=4

Subtract from both sides:

(-3x+15)-15=4-15

Simplify the arithmetic:

3x=415

Simplify the arithmetic:

3x=11

Divide both sides by :

(-3x)-3=-11-3

Cancel out the negatives:

3x3=-11-3

Simplify the fraction:

x=-11-3

Cancel out the negatives:

x=113

11 additional steps

(-2x+15)=-(x+4)

Expand the parentheses:

(-2x+15)=-x-4

Add to both sides:

(-2x+15)+x=(-x-4)+x

Group like terms:

(-2x+x)+15=(-x-4)+x

Simplify the arithmetic:

-x+15=(-x-4)+x

Group like terms:

-x+15=(-x+x)-4

Simplify the arithmetic:

x+15=4

Subtract from both sides:

(-x+15)-15=-4-15

Simplify the arithmetic:

x=415

Simplify the arithmetic:

x=19

Multiply both sides by :

-x·-1=-19·-1

Remove the one(s):

x=-19·-1

Simplify the arithmetic:

x=19

3. List the solutions

x=113,19
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x+15|
y=|x+4|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.