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Solution - Absolute value equations

Exact form: x=5,157
x=5 , \frac{15}{7}
Mixed number form: x=5,217
x=5 , 2\frac{1}{7}
Decimal form: x=5,2.143
x=5 , 2.143

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|25x|=|x-3|
without the absolute value bars:

|x|=|y||25x|=|x-3|
x=+y(25x)=(x-3)
x=-y(25x)=-(x-3)
+x=y(25x)=(x-3)
-x=y-(25x)=(x-3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||25x|=|x-3|
x=+y , +x=y(25x)=(x-3)
x=-y , -x=y(25x)=-(x-3)

2. Solve the two equations for x

15 additional steps

25x=(x-3)

Subtract from both sides:

(25x)-x=(x-3)-x

Group the coefficients:

(25-1)x=(x-3)-x

Convert the integer into a fraction:

(25+-55)x=(x-3)-x

Combine the fractions:

(2-5)5x=(x-3)-x

Combine the numerators:

-35x=(x-3)-x

Group like terms:

-35x=(x-x)-3

Simplify the arithmetic:

-35x=-3

Multiply both sides by inverse fraction :

(-35x)·5-3=-3·5-3

Move the negative sign from the denominator to the numerator:

-35x·-53=-3·5-3

Group like terms:

(-35·-53)x=-3·5-3

Multiply the coefficients:

(-3·-5)(5·3)x=-3·5-3

Simplify the arithmetic:

1x=-3·5-3

x=-3·5-3

Move the negative sign from the denominator to the numerator:

x=-3·-53

Multiply the fraction(s):

x=(-3·-5)3

Simplify the arithmetic:

x=5

13 additional steps

25x=-(x-3)

Expand the parentheses:

25x=-x+3

Add to both sides:

(25x)+x=(-x+3)+x

Group the coefficients:

(25+1)x=(-x+3)+x

Convert the integer into a fraction:

(25+55)x=(-x+3)+x

Combine the fractions:

(2+5)5x=(-x+3)+x

Combine the numerators:

75x=(-x+3)+x

Group like terms:

75x=(-x+x)+3

Simplify the arithmetic:

75x=3

Multiply both sides by inverse fraction :

(75x)·57=3·57

Group like terms:

(75·57)x=3·57

Multiply the coefficients:

(7·5)(5·7)x=3·57

Simplify the fraction:

x=3·57

Multiply the fraction(s):

x=(3·5)7

Simplify the arithmetic:

x=157

3. List the solutions

x=5,157
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|25x|
y=|x-3|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.