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Solution - Absolute value equations

Exact form: d=1.265,0.99
d=-1.265 , -0.99

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2.5d+1.8|=|7.4d+8|
without the absolute value bars:

|x|=|y||2.5d+1.8|=|7.4d+8|
x=+y(2.5d+1.8)=(7.4d+8)
x=y(2.5d+1.8)=(7.4d+8)
+x=y(2.5d+1.8)=(7.4d+8)
x=y(2.5d+1.8)=(7.4d+8)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2.5d+1.8|=|7.4d+8|
x=+y , +x=y(2.5d+1.8)=(7.4d+8)
x=y , x=y(2.5d+1.8)=(7.4d+8)

2. Solve the two equations for d

12 additional steps

(2.5d+1.8)=(7.4d+8)

Subtract from both sides:

(2.5d+1.8)-7.4d=(7.4d+8)-7.4d

Group like terms:

(2.5d-7.4d)+1.8=(7.4d+8)-7.4d

Simplify the arithmetic:

-4.9d+1.8=(7.4d+8)-7.4d

Group like terms:

-4.9d+1.8=(7.4d-7.4d)+8

Simplify the arithmetic:

4.9d+1.8=8

Subtract from both sides:

(-4.9d+1.8)-1.8=8-1.8

Simplify the arithmetic:

4.9d=81.8

Simplify the arithmetic:

4.9d=6.2

Divide both sides by :

(-4.9d)-4.9=6.2-4.9

Cancel out the negatives:

4.9d4.9=6.2-4.9

Simplify the arithmetic:

d=6.2-4.9

Move the negative sign from the denominator to the numerator:

d=-6.24.9

Simplify the arithmetic:

d=1.2653

11 additional steps

(2.5d+1.8)=-(7.4d+8)

Expand the parentheses:

(2.5d+1.8)=-7.4d-8

Add to both sides:

(2.5d+1.8)+7.4d=(-7.4d-8)+7.4d

Group like terms:

(2.5d+7.4d)+1.8=(-7.4d-8)+7.4d

Simplify the arithmetic:

9.9d+1.8=(-7.4d-8)+7.4d

Group like terms:

9.9d+1.8=(-7.4d+7.4d)-8

Simplify the arithmetic:

9.9d+1.8=8

Subtract from both sides:

(9.9d+1.8)-1.8=-8-1.8

Simplify the arithmetic:

9.9d=81.8

Simplify the arithmetic:

9.9d=9.8

Divide both sides by :

(9.9d)9.9=-9.89.9

Simplify the arithmetic:

d=-9.89.9

Simplify the arithmetic:

d=0.9899

3. List the solutions

d=1.265,0.99
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2.5d+1.8|
y=|7.4d+8|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.