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Solution - Absolute value equations

Exact form:

u = \frac{1}{6}, \frac{1}{2}

u=\frac{1}{6} , \frac{1}{2}

Decimal form:

u = 0.167, 0.5

u=0.167 , 0.5

See steps

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
$| x | = | y |$ → $x = \pm y$ and $| x | = | y |$ → $\pm x = y$
to write all four options of the equation
$| 2 u | = | - 4 u + 1 |$
without the absolute value bars:

$\| x \| = \| y \|$	$\| 2 u \| = \| - 4 u + 1 \|$
$x = + y$	$(2 u) = (- 4 u + 1)$
$x = - y$	$(2 u) = - (- 4 u + 1)$
$+ x = y$	$(2 u) = (- 4 u + 1)$
$- x = y$	$- (2 u) = (- 4 u + 1)$

When simplified, equations $x = + y$ and $+ x = y$ are the same and equations $x = - y$ and $- x = y$ are the same, so we end up with only 2 equations:

$\| x \| = \| y \|$	$\| 2 u \| = \| - 4 u + 1 \|$
$x = + y$ , $+ x = y$	$(2 u) = (- 4 u + 1)$
$x = - y$ , $- x = y$	$(2 u) = - (- 4 u + 1)$

2. Solve the two equations for u

5 additional steps

$2 u = (- 4 u + 1)$

Add to both sides:

$(2 u) + 4 u = (- 4 u + 1) + 4 u$

Simplify the arithmetic:

$6 u = (- 4 u + 1) + 4 u$

Group like terms:

$6 u = (- 4 u + 4 u) + 1$

Simplify the arithmetic:

$6 u = 1$

Divide both sides by :

$\frac{(6 u)}{6} = \frac{1}{6}$

Simplify the fraction:

$u = \frac{1}{6}$

8 additional steps

$2 u = - (- 4 u + 1)$

Expand the parentheses:

$2 u = 4 u - 1$

Subtract from both sides:

$(2 u) - 4 u = (4 u - 1) - 4 u$

Simplify the arithmetic:

$- 2 u = (4 u - 1) - 4 u$

Group like terms:

$- 2 u = (4 u - 4 u) - 1$

Simplify the arithmetic:

$- 2 u = - 1$

Divide both sides by :

$\frac{(- 2 u)}{- 2} = \frac{- 1}{- 2}$

Cancel out the negatives:

$\frac{2 u}{2} = \frac{- 1}{- 2}$

Simplify the fraction:

$u = \frac{- 1}{- 2}$

Cancel out the negatives:

$u = \frac{1}{2}$

3. List the solutions

$u = \frac{1}{6}, \frac{1}{2}$
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
$y = | 2 u |$
$y = | - 4 u + 1 |$
The equation is true where the two lines cross.

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Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

2. Solve the two equations for u

3. List the solutions

4. Graph

Why learn this

Terms and topics

Related links

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

2. Solve the two equations for u

3. List the solutions

4. Graph

Why learn this

Terms and topics

Related links

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