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Solution - Absolute value equations

Exact form: x=34,-12
x=\frac{3}{4} , -\frac{1}{2}
Decimal form: x=0.75,0.5
x=0.75 , -0.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x+4|=|7x+1|
without the absolute value bars:

|x|=|y||3x+4|=|7x+1|
x=+y(3x+4)=(7x+1)
x=y(3x+4)=(7x+1)
+x=y(3x+4)=(7x+1)
x=y(3x+4)=(7x+1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x+4|=|7x+1|
x=+y , +x=y(3x+4)=(7x+1)
x=y , x=y(3x+4)=(7x+1)

2. Solve the two equations for x

11 additional steps

(3x+4)=(7x+1)

Subtract from both sides:

(3x+4)-7x=(7x+1)-7x

Group like terms:

(3x-7x)+4=(7x+1)-7x

Simplify the arithmetic:

-4x+4=(7x+1)-7x

Group like terms:

-4x+4=(7x-7x)+1

Simplify the arithmetic:

4x+4=1

Subtract from both sides:

(-4x+4)-4=1-4

Simplify the arithmetic:

4x=14

Simplify the arithmetic:

4x=3

Divide both sides by :

(-4x)-4=-3-4

Cancel out the negatives:

4x4=-3-4

Simplify the fraction:

x=-3-4

Cancel out the negatives:

x=34

12 additional steps

(3x+4)=-(7x+1)

Expand the parentheses:

(3x+4)=-7x-1

Add to both sides:

(3x+4)+7x=(-7x-1)+7x

Group like terms:

(3x+7x)+4=(-7x-1)+7x

Simplify the arithmetic:

10x+4=(-7x-1)+7x

Group like terms:

10x+4=(-7x+7x)-1

Simplify the arithmetic:

10x+4=1

Subtract from both sides:

(10x+4)-4=-1-4

Simplify the arithmetic:

10x=14

Simplify the arithmetic:

10x=5

Divide both sides by :

(10x)10=-510

Simplify the fraction:

x=-510

Find the greatest common factor of the numerator and denominator:

x=(-1·5)(2·5)

Factor out and cancel the greatest common factor:

x=-12

3. List the solutions

x=34,-12
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3x+4|
y=|7x+1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.