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Solution - Absolute value equations

Exact form: x=76
x=\frac{7}{6}
Mixed number form: x=116
x=1\frac{1}{6}
Decimal form: x=1.167
x=1.167

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|3x2|+|3x+5|=0

Add |3x+5| to both sides of the equation:

|3x2|+|3x+5||3x+5|=|3x+5|

Simplify the arithmetic

|3x2|=|3x+5|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x2|=|3x+5|
without the absolute value bars:

|x|=|y||3x2|=|3x+5|
x=+y(3x2)=(3x+5)
x=y(3x2)=(3x+5)
+x=y(3x2)=(3x+5)
x=y(3x2)=(3x+5)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x2|=|3x+5|
x=+y , +x=y(3x2)=(3x+5)
x=y , x=y(3x2)=(3x+5)

3. Solve the two equations for x

6 additional steps

(3x-2)=-(-3x+5)

Expand the parentheses:

(3x-2)=3x-5

Subtract from both sides:

(3x-2)-3x=(3x-5)-3x

Group like terms:

(3x-3x)-2=(3x-5)-3x

Simplify the arithmetic:

-2=(3x-5)-3x

Group like terms:

-2=(3x-3x)-5

Simplify the arithmetic:

2=5

The statement is false:

2=5

The equation is false so it has no solution.

10 additional steps

(3x-2)=-(-(-3x+5))

NT_MSLUS_MAINSTEP_RESOLVE_DOUBLE_MINUS:

(3x-2)=-3x+5

Add to both sides:

(3x-2)+3x=(-3x+5)+3x

Group like terms:

(3x+3x)-2=(-3x+5)+3x

Simplify the arithmetic:

6x-2=(-3x+5)+3x

Group like terms:

6x-2=(-3x+3x)+5

Simplify the arithmetic:

6x2=5

Add to both sides:

(6x-2)+2=5+2

Simplify the arithmetic:

6x=5+2

Simplify the arithmetic:

6x=7

Divide both sides by :

(6x)6=76

Simplify the fraction:

x=76

4. Graph

Each line represents the function of one side of the equation:
y=|3x2|
y=|3x+5|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.