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Solution - Absolute value equations

Exact form: y=83,-8
y=\frac{8}{3} , -8
Mixed number form: y=223,-8
y=2\frac{2}{3} , -8
Decimal form: y=2.667,8
y=2.667 , -8

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3y8|=|3y+8|
without the absolute value bars:

|x|=|y||3y8|=|3y+8|
x=+y(3y8)=(3y+8)
x=y(3y8)=(3y+8)
+x=y(3y8)=(3y+8)
x=y(3y8)=(3y+8)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3y8|=|3y+8|
x=+y , +x=y(3y8)=(3y+8)
x=y , x=y(3y8)=(3y+8)

2. Solve the two equations for y

11 additional steps

(3y-8)=(-3y+8)

Add to both sides:

(3y-8)+3y=(-3y+8)+3y

Group like terms:

(3y+3y)-8=(-3y+8)+3y

Simplify the arithmetic:

6y-8=(-3y+8)+3y

Group like terms:

6y-8=(-3y+3y)+8

Simplify the arithmetic:

6y8=8

Add to both sides:

(6y-8)+8=8+8

Simplify the arithmetic:

6y=8+8

Simplify the arithmetic:

6y=16

Divide both sides by :

(6y)6=166

Simplify the fraction:

y=166

Find the greatest common factor of the numerator and denominator:

y=(8·2)(3·2)

Factor out and cancel the greatest common factor:

y=83

5 additional steps

(3y-8)=-(-3y+8)

Expand the parentheses:

(3y-8)=3y-8

Subtract from both sides:

(3y-8)-3y=(3y-8)-3y

Group like terms:

(3y-3y)-8=(3y-8)-3y

Simplify the arithmetic:

-8=(3y-8)-3y

Group like terms:

-8=(3y-3y)-8

Simplify the arithmetic:

8=8

3. List the solutions

y=83,-8
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3y8|
y=|3y+8|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.