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Solution - Absolute value equations

Exact form: w=-4,-13
w=-4 , -\frac{1}{3}
Decimal form: w=4,0.333
w=-4 , -0.333

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|4w+5|=|2w3|
without the absolute value bars:

|x|=|y||4w+5|=|2w3|
x=+y(4w+5)=(2w3)
x=y(4w+5)=(2w3)
+x=y(4w+5)=(2w3)
x=y(4w+5)=(2w3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||4w+5|=|2w3|
x=+y , +x=y(4w+5)=(2w3)
x=y , x=y(4w+5)=(2w3)

2. Solve the two equations for w

11 additional steps

(4w+5)=(2w-3)

Subtract from both sides:

(4w+5)-2w=(2w-3)-2w

Group like terms:

(4w-2w)+5=(2w-3)-2w

Simplify the arithmetic:

2w+5=(2w-3)-2w

Group like terms:

2w+5=(2w-2w)-3

Simplify the arithmetic:

2w+5=3

Subtract from both sides:

(2w+5)-5=-3-5

Simplify the arithmetic:

2w=35

Simplify the arithmetic:

2w=8

Divide both sides by :

(2w)2=-82

Simplify the fraction:

w=-82

Find the greatest common factor of the numerator and denominator:

w=(-4·2)(1·2)

Factor out and cancel the greatest common factor:

w=4

12 additional steps

(4w+5)=-(2w-3)

Expand the parentheses:

(4w+5)=-2w+3

Add to both sides:

(4w+5)+2w=(-2w+3)+2w

Group like terms:

(4w+2w)+5=(-2w+3)+2w

Simplify the arithmetic:

6w+5=(-2w+3)+2w

Group like terms:

6w+5=(-2w+2w)+3

Simplify the arithmetic:

6w+5=3

Subtract from both sides:

(6w+5)-5=3-5

Simplify the arithmetic:

6w=35

Simplify the arithmetic:

6w=2

Divide both sides by :

(6w)6=-26

Simplify the fraction:

w=-26

Find the greatest common factor of the numerator and denominator:

w=(-1·2)(3·2)

Factor out and cancel the greatest common factor:

w=-13

3. List the solutions

w=-4,-13
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|4w+5|
y=|2w3|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.