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Solution - Absolute value equations

Exact form: x=1,5
x=1 , -5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|4x+2|=|2x+8|
without the absolute value bars:

|x|=|y||4x+2|=|2x+8|
x=+y(4x+2)=(2x+8)
x=y(4x+2)=(2x+8)
+x=y(4x+2)=(2x+8)
x=y(4x+2)=(2x+8)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||4x+2|=|2x+8|
x=+y , +x=y(4x+2)=(2x+8)
x=y , x=y(4x+2)=(2x+8)

2. Solve the two equations for x

10 additional steps

(4x+2)=(-2x+8)

Add to both sides:

(4x+2)+2x=(-2x+8)+2x

Group like terms:

(4x+2x)+2=(-2x+8)+2x

Simplify the arithmetic:

6x+2=(-2x+8)+2x

Group like terms:

6x+2=(-2x+2x)+8

Simplify the arithmetic:

6x+2=8

Subtract from both sides:

(6x+2)-2=8-2

Simplify the arithmetic:

6x=82

Simplify the arithmetic:

6x=6

Divide both sides by :

(6x)6=66

Simplify the fraction:

x=66

Simplify the fraction:

x=1

12 additional steps

(4x+2)=-(-2x+8)

Expand the parentheses:

(4x+2)=2x-8

Subtract from both sides:

(4x+2)-2x=(2x-8)-2x

Group like terms:

(4x-2x)+2=(2x-8)-2x

Simplify the arithmetic:

2x+2=(2x-8)-2x

Group like terms:

2x+2=(2x-2x)-8

Simplify the arithmetic:

2x+2=8

Subtract from both sides:

(2x+2)-2=-8-2

Simplify the arithmetic:

2x=82

Simplify the arithmetic:

2x=10

Divide both sides by :

(2x)2=-102

Simplify the fraction:

x=-102

Find the greatest common factor of the numerator and denominator:

x=(-5·2)(1·2)

Factor out and cancel the greatest common factor:

x=5

3. List the solutions

x=1,5
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|4x+2|
y=|2x+8|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.