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Solution - Absolute value equations

Exact form: x=-12
x=-\frac{1}{2}
Decimal form: x=0.5
x=-0.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|4x+7|=|4x3|
without the absolute value bars:

|x|=|y||4x+7|=|4x3|
x=+y(4x+7)=(4x3)
x=y(4x+7)=(4x3)
+x=y(4x+7)=(4x3)
x=y(4x+7)=(4x3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||4x+7|=|4x3|
x=+y , +x=y(4x+7)=(4x3)
x=y , x=y(4x+7)=(4x3)

2. Solve the two equations for x

5 additional steps

(4x+7)=(4x-3)

Subtract from both sides:

(4x+7)-4x=(4x-3)-4x

Group like terms:

(4x-4x)+7=(4x-3)-4x

Simplify the arithmetic:

7=(4x-3)-4x

Group like terms:

7=(4x-4x)-3

Simplify the arithmetic:

7=3

The statement is false:

7=3

The equation is false so it has no solution.

12 additional steps

(4x+7)=-(4x-3)

Expand the parentheses:

(4x+7)=-4x+3

Add to both sides:

(4x+7)+4x=(-4x+3)+4x

Group like terms:

(4x+4x)+7=(-4x+3)+4x

Simplify the arithmetic:

8x+7=(-4x+3)+4x

Group like terms:

8x+7=(-4x+4x)+3

Simplify the arithmetic:

8x+7=3

Subtract from both sides:

(8x+7)-7=3-7

Simplify the arithmetic:

8x=37

Simplify the arithmetic:

8x=4

Divide both sides by :

(8x)8=-48

Simplify the fraction:

x=-48

Find the greatest common factor of the numerator and denominator:

x=(-1·4)(2·4)

Factor out and cancel the greatest common factor:

x=-12

3. Graph

Each line represents the function of one side of the equation:
y=|4x+7|
y=|4x3|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.