Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: x=-10,227
x=-10 , \frac{22}{7}
Mixed number form: x=-10,317
x=-10 , 3\frac{1}{7}
Decimal form: x=10,3.143
x=-10 , 3.143

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x+4|=|2x26|
without the absolute value bars:

|x|=|y||5x+4|=|2x26|
x=+y(5x+4)=(2x26)
x=y(5x+4)=(2x26)
+x=y(5x+4)=(2x26)
x=y(5x+4)=(2x26)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x+4|=|2x26|
x=+y , +x=y(5x+4)=(2x26)
x=y , x=y(5x+4)=(2x26)

2. Solve the two equations for x

11 additional steps

(5x+4)=(2x-26)

Subtract from both sides:

(5x+4)-2x=(2x-26)-2x

Group like terms:

(5x-2x)+4=(2x-26)-2x

Simplify the arithmetic:

3x+4=(2x-26)-2x

Group like terms:

3x+4=(2x-2x)-26

Simplify the arithmetic:

3x+4=26

Subtract from both sides:

(3x+4)-4=-26-4

Simplify the arithmetic:

3x=264

Simplify the arithmetic:

3x=30

Divide both sides by :

(3x)3=-303

Simplify the fraction:

x=-303

Find the greatest common factor of the numerator and denominator:

x=(-10·3)(1·3)

Factor out and cancel the greatest common factor:

x=10

10 additional steps

(5x+4)=-(2x-26)

Expand the parentheses:

(5x+4)=-2x+26

Add to both sides:

(5x+4)+2x=(-2x+26)+2x

Group like terms:

(5x+2x)+4=(-2x+26)+2x

Simplify the arithmetic:

7x+4=(-2x+26)+2x

Group like terms:

7x+4=(-2x+2x)+26

Simplify the arithmetic:

7x+4=26

Subtract from both sides:

(7x+4)-4=26-4

Simplify the arithmetic:

7x=264

Simplify the arithmetic:

7x=22

Divide both sides by :

(7x)7=227

Simplify the fraction:

x=227

3. List the solutions

x=-10,227
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5x+4|
y=|2x26|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.