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Solution - Absolute value equations

Exact form: x=4,1
x=4 , 1

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x8|=|3x|
without the absolute value bars:

|x|=|y||5x8|=|3x|
x=+y(5x8)=(3x)
x=y(5x8)=(3x)
+x=y(5x8)=(3x)
x=y(5x8)=(3x)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x8|=|3x|
x=+y , +x=y(5x8)=(3x)
x=y , x=y(5x8)=(3x)

2. Solve the two equations for x

10 additional steps

(5x-8)=3x

Subtract from both sides:

(5x-8)-3x=(3x)-3x

Group like terms:

(5x-3x)-8=(3x)-3x

Simplify the arithmetic:

2x-8=(3x)-3x

Simplify the arithmetic:

2x8=0

Add to both sides:

(2x-8)+8=0+8

Simplify the arithmetic:

2x=0+8

Simplify the arithmetic:

2x=8

Divide both sides by :

(2x)2=82

Simplify the fraction:

x=82

Find the greatest common factor of the numerator and denominator:

x=(4·2)(1·2)

Factor out and cancel the greatest common factor:

x=4

8 additional steps

(5x-8)=-3x

Add to both sides:

(5x-8)+8=(-3x)+8

Simplify the arithmetic:

5x=(-3x)+8

Add to both sides:

(5x)+3x=((-3x)+8)+3x

Simplify the arithmetic:

8x=((-3x)+8)+3x

Group like terms:

8x=(-3x+3x)+8

Simplify the arithmetic:

8x=8

Divide both sides by :

(8x)8=88

Simplify the fraction:

x=88

Simplify the fraction:

x=1

3. List the solutions

x=4,1
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5x8|
y=|3x|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.