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Solution - Absolute value equations

Exact form: x=-32,34
x=-\frac{3}{2} , \frac{3}{4}
Mixed number form: x=-112,34
x=-1\frac{1}{2} , \frac{3}{4}
Decimal form: x=1.5,0.75
x=-1.5 , 0.75

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|6x|=|2x6|
without the absolute value bars:

|x|=|y||6x|=|2x6|
x=+y(6x)=(2x6)
x=y(6x)=(2x6)
+x=y(6x)=(2x6)
x=y(6x)=(2x6)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||6x|=|2x6|
x=+y , +x=y(6x)=(2x6)
x=y , x=y(6x)=(2x6)

2. Solve the two equations for x

7 additional steps

6x=(2x-6)

Subtract from both sides:

(6x)-2x=(2x-6)-2x

Simplify the arithmetic:

4x=(2x-6)-2x

Group like terms:

4x=(2x-2x)-6

Simplify the arithmetic:

4x=6

Divide both sides by :

(4x)4=-64

Simplify the fraction:

x=-64

Find the greatest common factor of the numerator and denominator:

x=(-3·2)(2·2)

Factor out and cancel the greatest common factor:

x=-32

8 additional steps

6x=-(2x-6)

Expand the parentheses:

6x=2x+6

Add to both sides:

(6x)+2x=(-2x+6)+2x

Simplify the arithmetic:

8x=(-2x+6)+2x

Group like terms:

8x=(-2x+2x)+6

Simplify the arithmetic:

8x=6

Divide both sides by :

(8x)8=68

Simplify the fraction:

x=68

Find the greatest common factor of the numerator and denominator:

x=(3·2)(4·2)

Factor out and cancel the greatest common factor:

x=34

3. List the solutions

x=-32,34
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|6x|
y=|2x6|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.