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Solution - Absolute value equations

Exact form: x=6,413
x=6 , \frac{4}{13}
Decimal form: x=6,0.308
x=6 , 0.308

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|7x5|=|6x+1|
without the absolute value bars:

|x|=|y||7x5|=|6x+1|
x=+y(7x5)=(6x+1)
x=y(7x5)=(6x+1)
+x=y(7x5)=(6x+1)
x=y(7x5)=(6x+1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||7x5|=|6x+1|
x=+y , +x=y(7x5)=(6x+1)
x=y , x=y(7x5)=(6x+1)

2. Solve the two equations for x

7 additional steps

(7x-5)=(6x+1)

Subtract from both sides:

(7x-5)-6x=(6x+1)-6x

Group like terms:

(7x-6x)-5=(6x+1)-6x

Simplify the arithmetic:

x-5=(6x+1)-6x

Group like terms:

x-5=(6x-6x)+1

Simplify the arithmetic:

x5=1

Add to both sides:

(x-5)+5=1+5

Simplify the arithmetic:

x=1+5

Simplify the arithmetic:

x=6

10 additional steps

(7x-5)=-(6x+1)

Expand the parentheses:

(7x-5)=-6x-1

Add to both sides:

(7x-5)+6x=(-6x-1)+6x

Group like terms:

(7x+6x)-5=(-6x-1)+6x

Simplify the arithmetic:

13x-5=(-6x-1)+6x

Group like terms:

13x-5=(-6x+6x)-1

Simplify the arithmetic:

13x5=1

Add to both sides:

(13x-5)+5=-1+5

Simplify the arithmetic:

13x=1+5

Simplify the arithmetic:

13x=4

Divide both sides by :

(13x)13=413

Simplify the fraction:

x=413

3. List the solutions

x=6,413
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|7x5|
y=|6x+1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.