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Solution - Absolute value equations

Exact form: x=-6,-103
x=-6 , -\frac{10}{3}
Mixed number form: x=-6,-313
x=-6 , -3\frac{1}{3}
Decimal form: x=6,3.333
x=-6 , -3.333

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x+8|=|x+2|
without the absolute value bars:

|x|=|y||2x+8|=|x+2|
x=+y(2x+8)=(x+2)
x=y(2x+8)=(x+2)
+x=y(2x+8)=(x+2)
x=y(2x+8)=(x+2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x+8|=|x+2|
x=+y , +x=y(2x+8)=(x+2)
x=y , x=y(2x+8)=(x+2)

2. Solve the two equations for x

7 additional steps

(2x+8)=(x+2)

Subtract from both sides:

(2x+8)-x=(x+2)-x

Group like terms:

(2x-x)+8=(x+2)-x

Simplify the arithmetic:

x+8=(x+2)-x

Group like terms:

x+8=(x-x)+2

Simplify the arithmetic:

x+8=2

Subtract from both sides:

(x+8)-8=2-8

Simplify the arithmetic:

x=28

Simplify the arithmetic:

x=6

10 additional steps

(2x+8)=-(x+2)

Expand the parentheses:

(2x+8)=-x-2

Add to both sides:

(2x+8)+x=(-x-2)+x

Group like terms:

(2x+x)+8=(-x-2)+x

Simplify the arithmetic:

3x+8=(-x-2)+x

Group like terms:

3x+8=(-x+x)-2

Simplify the arithmetic:

3x+8=2

Subtract from both sides:

(3x+8)-8=-2-8

Simplify the arithmetic:

3x=28

Simplify the arithmetic:

3x=10

Divide both sides by :

(3x)3=-103

Simplify the fraction:

x=-103

3. List the solutions

x=-6,-103
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x+8|
y=|x+2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.