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Solution - Absolute value equations

Exact form: x=194,1912
x=\frac{19}{4} , \frac{19}{12}
Mixed number form: x=434,1712
x=4\frac{3}{4} , 1\frac{7}{12}
Decimal form: x=4.75,1.583
x=4.75 , 1.583

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|8x19|=|4x|
without the absolute value bars:

|x|=|y||8x19|=|4x|
x=+y(8x19)=(4x)
x=y(8x19)=(4x)
+x=y(8x19)=(4x)
x=y(8x19)=(4x)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||8x19|=|4x|
x=+y , +x=y(8x19)=(4x)
x=y , x=y(8x19)=(4x)

2. Solve the two equations for x

8 additional steps

(8x-19)=4x

Subtract from both sides:

(8x-19)-4x=(4x)-4x

Group like terms:

(8x-4x)-19=(4x)-4x

Simplify the arithmetic:

4x-19=(4x)-4x

Simplify the arithmetic:

4x19=0

Add to both sides:

(4x-19)+19=0+19

Simplify the arithmetic:

4x=0+19

Simplify the arithmetic:

4x=19

Divide both sides by :

(4x)4=194

Simplify the fraction:

x=194

7 additional steps

(8x-19)=-4x

Add to both sides:

(8x-19)+19=(-4x)+19

Simplify the arithmetic:

8x=(-4x)+19

Add to both sides:

(8x)+4x=((-4x)+19)+4x

Simplify the arithmetic:

12x=((-4x)+19)+4x

Group like terms:

12x=(-4x+4x)+19

Simplify the arithmetic:

12x=19

Divide both sides by :

(12x)12=1912

Simplify the fraction:

x=1912

3. List the solutions

x=194,1912
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|8x19|
y=|4x|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.